Calculate the fault current in each phase for a L-G fault occurs at primary of transformer-2 for the system shown in below fig.All the reactaces are given in p.u on 100 MVA base E- 16 x = j0.2 Line X,X j0.11 X = j0.33 2= j0.22 K- J0.15 -0.16 Xy = 30.17 Xo - j0.06 x, = x2 = j0.10 X "x2 "Xg- 0.10 -12.7831 -j2.3781p.u None -j2.2668 p.u
Calculate the fault current in each phase for a L-G fault occurs at primary of transformer-2 for the system shown in below fig.All the reactaces are given in p.u on 100 MVA base E- 16 x = j0.2 Line X,X j0.11 X = j0.33 2= j0.22 K- J0.15 -0.16 Xy = 30.17 Xo - j0.06 x, = x2 = j0.10 X "x2 "Xg- 0.10 -12.7831 -j2.3781p.u None -j2.2668 p.u
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![Calculate the fault current in each phase for a L-G fault occurs at primary of transformer-2 for the system shown in below fig.All the reactaces are given in p.u on 100 MVA base
E= 1/0º
x = j0.2
Line
X =x, = j0.11
Xp = j0.33
X2 = ]0.22
xe = 30.15
- j0.16
X2 = J0.17
Xo = j0.06
X, = x2 = j0.10
X1 =x2 = xg = 0.10
-j2.7831
-j2.3781p.u
None
-j2.2668 p.u
ele](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F01e25eed-d1d8-401a-aefa-538be042715d%2Fd4a8aab0-a3e6-4c78-bcba-6304c9a32c1f%2Fusekn5m_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the fault current in each phase for a L-G fault occurs at primary of transformer-2 for the system shown in below fig.All the reactaces are given in p.u on 100 MVA base
E= 1/0º
x = j0.2
Line
X =x, = j0.11
Xp = j0.33
X2 = ]0.22
xe = 30.15
- j0.16
X2 = J0.17
Xo = j0.06
X, = x2 = j0.10
X1 =x2 = xg = 0.10
-j2.7831
-j2.3781p.u
None
-j2.2668 p.u
ele
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