calculate the Ergun parameter, ?. using the following parameters, you will need to do some unit conversion, i think i did it correctly i have added the eqautions that need to be used, α -m = 104.4 lbm/hourAirOperating conditions:Feed (air):Catalyst properties:Reactor dimensions:a =T = 260 °C (isothermal)Mo = 0.0673 lbm/ (ft * hr)Pcat = 72 lbm/ft³p = 0.361.5 inch SCH 40 pipe(13) *2* G*(1¹17) & bPo*Po*9c*Dp*Pcat* AcAc2*GPo Po 9c*Dp*Pcat* AcG = p*um * AcP₁ = 21162.266lbfft²& gc=Catalyst particles150*(1-0)*μDp104.4 lbmhrDpart== 4.17 x 108.=+ 1.75* Gor150*(1-φ)*μDp10.01414 ft²lbm*ftlbf*hr2P = 10 atmPo = 0.413 lbm/ft³Dpart = 0.64inchesAc = 0.01414 ft²0.64 | 1 ft0.641/712 in=+1.75 G → a= a*bG]= 7383.3100.053 ftlbmft² * hr

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Answered: calculate the Ergun parameter, ?. using…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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calculate the Ergun parameter, ?. using the following parameters,

you will need to do some unit conversion, i think i did it correctly i have added the eqautions that need to be used,

α -
m = 104.4 lbm/hour
Air
Operating conditions:
Feed (air):
Catalyst properties:
Reactor dimensions:
a =
T = 260 °C (isothermal)
Mo = 0.0673 lbm/ (ft * hr)
Pcat = 72 lbm/ft³
p = 0.36
1.5 inch SCH 40 pipe
(13) *
2* G
*
(1¹17) & b
Po*Po*9c*Dp*Pcat* Ac
Ac
2*G
Po Po 9c*Dp*Pcat* Ac
G = p*um * Ac
P₁ = 21162.266
lbf
ft²
& gc
=
Catalyst particles
150*(1-0)*μ
Dp
104.4 lbm
hr
Dpart
=
= 4.17 x 108.
=
+ 1.75* Gor
150*(1-φ)*μ
Dp
1
0.01414 ft²
lbm*ft
lbf*hr2
P = 10 atm
Po = 0.413 lbm/ft³
Dpart = 0.64inches
Ac = 0.01414 ft²
0.64 | 1 ft
0.641/7
12 in
=
+1.75 G → a= a*b
G]
= 7383.310
0.053 ft
lbm
ft² * hr

Expert Solution

Step 1: given

$g i v e n space equals space T space equals space 260 to the power of o c mu subscript o space equals space 0.0673 space l b subscript m divided by left parenthesis f t. h r right parenthesis P space equals space 10 space a t m rho subscript o space equals space 0.413 space l b m divided by f t cubed rho subscript c a t space end subscript equals space 72 space l b m divided by f t cubed empty set space equals space 0.36 space a n d space A subscript c space equals space 0.01414 space f t squared$