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Calculate the enthalpy of the reaction 4B(s) + 302 (9)→2B2O3 (s) given the following pertinent information: A. B2O3 (s) + 3H2O(g)→302(g) +B2H6 (g), A;H¡ = +2035 kJ mol-1 В. 2В (8) + зН2(9)-B,H. (9), c. H2 (9) + O2(g)→H2O(1), A,H§ = +36 kJ mol-1 A,H¿ = -285 kJ mol¬1 A, H§ = +44 kJ mol¬! D. H2O(1)→H2O(g),

Calculate the enthalpy of the reaction 4B(s) + 302 (9)→2B2O3 (s) given the following pertinent information: A. B2O3 (s) + 3H2O(g)→302(g) +B2H6 (g), A;H¡ = +2035 kJ mol-1 В. 2В (8) + зН2(9)-B,H. (9), c. H2 (9) + O2(g)→H2O(1), A,H§ = +36 kJ mol-1 A,H¿ = -285 kJ mol¬1 A, H§ = +44 kJ mol¬! D. H2O(1)→H2O(g),

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Hess's law states that "the heat released or absorbed in a chemical process is the same whether the process takes place in one or in several steps." It is important to recall the following rules: 1. When two reactions are added, their enthalpy values are added. 2. When a reaction is reversed, the sign of its enthalpy value changes. Part B 3. When the coefficients of a reaction are multiplied by a factor, the enthalpy value is multiplied by that same factor. Calculate the enthalpy of the reaction 4B(s) + 302 (9)→2B2O3(s) given the following pertinent information: A. B2O3(s) + 3H20(g)→302(g) +B2H6 (9), A;H = B. 2B(s) + 3H2 (g)→B2H6 (g), c. H2 (9) + 02(g)→H2O(1), +2035 kJ mol-1 A, H = +36 kJ mol-1 A,H = -285 kJ mol¬1 A, Hj = +44 kJ mol-1 D. H2 O(1)→H2O(g), Express your answer with the appropriate units. View Available Hint(s) HẢ ? A,H° = Value Units Submit
Transcribed Image Text:Hess's law states that "the heat released or absorbed in a chemical process is the same whether the process takes place in one or in several steps." It is important to recall the following rules: 1. When two reactions are added, their enthalpy values are added. 2. When a reaction is reversed, the sign of its enthalpy value changes. Part B 3. When the coefficients of a reaction are multiplied by a factor, the enthalpy value is multiplied by that same factor. Calculate the enthalpy of the reaction 4B(s) + 302 (9)→2B2O3(s) given the following pertinent information: A. B2O3(s) + 3H20(g)→302(g) +B2H6 (9), A;H = B. 2B(s) + 3H2 (g)→B2H6 (g), c. H2 (9) + 02(g)→H2O(1), +2035 kJ mol-1 A, H = +36 kJ mol-1 A,H = -285 kJ mol¬1 A, Hj = +44 kJ mol-1 D. H2 O(1)→H2O(g), Express your answer with the appropriate units. View Available Hint(s) HẢ ? A,H° = Value Units Submit
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