calculate the enthalpy of neutralization between naoh and hci. the following values provides mass of cup 4.413g initial temp 15.7 cel final temo 18.0C total mass of cup 88.153g mass of hci 40.08ml nass of naoh 45.67ml use hess law MOLARITY OF HCI: 0.502 +/- 0.001M MOLARITY OF NaOH: 0.500 +/- 0.001M
calculate the enthalpy of neutralization between naoh and hci. the following values provides mass of cup 4.413g initial temp 15.7 cel final temo 18.0C total mass of cup 88.153g mass of hci 40.08ml nass of naoh 45.67ml use hess law MOLARITY OF HCI: 0.502 +/- 0.001M MOLARITY OF NaOH: 0.500 +/- 0.001M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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calculate the enthalpy of neutralization between naoh and hci.
the following values provides
mass of cup 4.413g
initial temp 15.7 cel final temo 18.0C
total mass of cup 88.153g
mass of hci 40.08ml
nass of naoh 45.67ml
use hess law
MOLARITY OF HCI: 0.502 +/- 0.001M
MOLARITY OF NaOH: 0.500 +/- 0.001M
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