Calculate the Enthalpy (AH, in kJ/mol) for the following reaction from the heat ofrxnformation data given below (Hint: Carefully check the state symbols in this reaction):4 NO (g) + 6 H20 (I) →4 NH3 (g) + 5 O2 (g)= ?NH3(g)AH, = - 45.9 kJ/molNO(g)= + 90.3 kJ/molH20(1)AH285.8 kJ/mol= -H20(g)AH = - 241.80 kJ/molf Calculate the Enthalpy (AH, in kJ/mol) using the appropriate bond dissociationrxn ?nergies (BDES) listed below (Hint: Draw out the Lewis structures of each species first):2 H20 (g) + CO2 (g) → 2 O2 (g) + CH4 (g)Bond TypeBDES (kJ/mol).O-H467C-H413O=0498C=O799"Based on the enthalpy value you calculated in part (a), discuss what this tells you from amolecular-level perspective.

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Calculate the Enthalpy (AH , in kJ/mol) for the following reaction from the heat of formation data given below (Hint: Carefully check the state symbols in this reaction): 4 NO (g) + 6 H2O (1) 4 NH3 (g) + 5 O2 (g) AH = ? rxn NH3(g) AH =- 45.9 kJ/mol NO(g) AH : = + 90.3 kJ/mol H20(1) AH° = - 285.8 kJ/mol H2O(g) AH° = - 241.80 kJ/mol

Calculate the Enthalpy (AH , in kJ/mol) for the following reaction from the heat of formation data given below (Hint: Carefully check the state symbols in this reaction): 4 NO (g) + 6 H2O (1) 4 NH3 (g) + 5 O2 (g) AH = ? rxn NH3(g) AH =- 45.9 kJ/mol NO(g) AH : = + 90.3 kJ/mol H20(1) AH° = - 285.8 kJ/mol H2O(g) AH° = - 241.80 kJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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