Calculate the change of enthalpyfor the reaction CH4 (g) + NH3 (g) --> HCN (g) +3H2 (g) from thefollowing reactions:Reaction 1: N2 (g) + 3H2 (g) -->2NH3 (g)Change in enthalpy: -91.8 kJ/molReaction 2: C (s, graphite) + 2H2(g) --> CH4 (g)Change in enthalply: -74.9 kJ/molReaction 3: H2 (g) + 2C (s,graphite) + N2 (g) --> 2HCN (g)Change in enthalpy: +270.3kJ/molInclude the following:The numerical answer withcorrect units.• State which reactions, if any,you had to "Flip".• State which reactions you hadto multiply, if any, to get thecorrect amount of thecompound. Also, include howmuch you multiplied thereaction by.

Given reactions N2 (g) + 3H2(g) -----------> 2NH3(g) ∆H=-91.8kJ/mol. _____(1) C(s,graphite)…

Answered: Calculate the change of enthalpy for…

Science

Chemistry

Calculate the change of enthalpy for the reaction CH4 (g) + NH3 (g) - -> HCN (g) +3H2 (g) from the following reactions:

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Ethylene glycol, HOCH2CH2OH, is used as antifreeze. It is produced from ethylene oxide, C2 H40, by the reaction C2 H4O(g) + H,0(1) HOCH, CH,OH(!) Use Hess's law to obtain the enthalpy change for this reaction from the following enthalpy changes: 2C, HO(g) + 502(9) → 4CO2 (9) + 4H,0(1) AH =-2612.2 kJ HOCH, CH, OH(1) + O2 (9) → 2002 (9) + 3H,0(1) AH=-1189.8 kJ Enthalpy change = kJ %3D
(b) An aqueous solution of acetic acid can be prepared by the reaction of ethanol with oxygen : CH3CH2OH (1) + O2 (g) –→ CH3COOH (1) + H2O (1) Write thermochemical equations for enthalpy of formation of the given compounds and calculate AH for the reaction, given the following data. Enthalpy of formation, AHf (kJmol") -277.8 Compound CH;CH2OH (1) CH3COOH (I) H2O (1) -485.0 -286.0
Calculate the standard enthalpy of formation for C3H6O (l) from its combustion using the following data: Enthalpy of this combustion is -1793 kJ ( you must write a balanced reaction first).
The combustion of propanal (C3H6O; 58.079 g/mol) is studied in a bomb calorime an experiment in which the volume does not change. The heat of combustion as measured in this calorimetry experiment is found to be -26.20 kJ/g of propanal at 298 K. What is the molar enthalpy of combustion for this reaction? C3H6O(l) + 4 O₂(g) → 3 CO₂(g) + 3 H₂O(l) -> -1519.2 kJ/mol -1524.1 kJ/mol -1521.7 kJ/mol O-26.20 kJ/mol -1525.4 kJ/mol -1526.7 kJ/mol
When 1.0 mol N204(g) is formed from 2.0 mol NO2(g) under constant pressure (1 atm) at 298 K, please calculate:(a) the reaction enthalpy (ArH) of this reaction according to the standard molar formation enthalpy of NO2(g) and N204(g)at 298 K, +33.85 kJ/mol and +9.66 kJ/mol, respectively.(b) the entropy change in the surrounding. (hint: equal to the heat received by surrounding / temperature of thesurrounding)
Using the standard enthalpies of formation, what is the standard enthalpy of reaction? CO(g) + H,O(g) –→ CO,(g) + H,(g) AHân = kJ
2. Calculating enthalpy: AH = -206 kJ mol¹¹, 3 Fe(s) + 2 O₂(g) → Fe3O4 (S) AH = -136 kJ mol-¹, a) Given 2Fe(s) + 1.5 O₂(g) → Fe₂O3 (S) determine AH, for the following reaction: 4Fe₂O3(s) + Fe(s) → 3Fe3O4 (s) Is this reaction exothermic or endothermic? Is this enough information to inform whether this reaction occurs or not? O b) Given AH vap of water at 373 K = 40.7 kJ mol¹¹, C₂(l)=75.2 J mol¹¹K²¹ and ₂(g)=33.6 J mol¹¹K²¹, calculate AHvap of water at 298 K.
Determine the enthalpy for the production of 5.0 g of H2 in the following target equation, making use of the known equations given below. CH4 (g) + NH3 (g) → HCN(g) + 3H2 (g) Using the following given equations: N2 (g)+3H2 (g) → 2NH3 (g) ΔH=− 91.8kJ C(s)+2H2 (g) → CH4 (g) ΔH=− 74.9kJ H2(g) + 2C(s) + N2 (g) → 2HCN(g) ΔH= + 270.3 kJ
1 If the standard enthalpy of cembustion of gaseous cyclopropane, C3H6, is -2091.2 kJ mol- at 25 C, calculate the standard enthalpy of formation of the compound at 298 K. (The standard enthalpy of combustion is the heat of combustion of one mole of a compound to the most stable combustion products, which are CO2(g) and H20(1) in the case of hydrocarbons. The standard enthalpy of formation is the enthalpy of formation of one mole of a compound from its constituent elements, the compound and its constituent elements in their standard states.)
Hydrobromic acid (HBr) is a commonly used acid for adding bromine to organic compounds. As bromine makes for an easily replaceable substituent, these bromine precursors are a necessary part of a vast amount of organic eynthesis, Calculate the reaction enthalpy for the synthesis of HBr according to H2(g) + Bra)2Br(g) Use the following information: NH3(g) +HBr(g) → NHABr(s) AH =-188.32 kJ Na(g) + 3H2(g) → 2NH3(g) AH = -92.22 kJ N2(g) + 4H2(g) + Br2(1) → 2NHABr(s) AH =-541.66 kJ a. AH =-728 kmol b. AH =-1010.52 KJjmol C. AH =-826.08 KJ/mol d. AH =728 kJ/mol e. AH = -257.24 kJ/mol Clear my choice
（1）Consider the reaction: 2A (g) + 3 B (g) → 2 C (g) ΔHrxn = +254.3 kJ What will be the enthalpy change (in kJ) if 0.471 mol B reacts in excess A? （2）Consider the reaction: C (s) + O2 (g) → CO2 (g) ΔHrxn = -393.5 kJ What mass of carbon (in g) must be reacted via this mechanism to release 581.2 kJ of heat?