Calculate the energy released for the consumption of 350mL of 6.5 M LIOH in the following neutralization reaction with the given heat of neutralization. LIOH(aq) + HCl(aq) → LİCI(s) + H20(P) AH° = -18.61 kJ/mol

Calculate the energy released for the consumption of 350mL of 6.5 M LIOH in the following neutralization reaction with the given heat of neutralization. LIOH(aq) + HCl(aq) → LİCI(s) + H20(P) AH° = -18.61 kJ/mol

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter17: Chemcial Thermodynamics

Section: Chapter Questions

Problem 17.75QE

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Concept explainers

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

Calculate the energy released for the consumption of 350mL of 6.5 M LIOH in the following neutralization reaction with the given
heat of neutralization.
LIOH(aq) + HCl(aq) → LİC((s) + H2O(e)
AH° = -18.61 kJ/mol
A) -42,337 kJ
B) 42.34 kJ
-42.34 kJ
D
42,337 kJ

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