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Calculate the energy of combustion per gram of Olive Oil (kJ/g) if 29.9 ml. of water is placed in the test tube and the temperature changes from 22.9 °C to 44.6 °C. The initial mass of the spirit burner is 204.60 g and the final mass is 204.51g. State your answer with correct significant digits.

Calculate the energy of combustion per gram of Olive Oil (kJ/g) if 29.9 ml. of water is placed in the test tube and the temperature changes from 22.9 °C to 44.6 °C. The initial mass of the spirit burner is 204.60 g and the final mass is 204.51g. State your answer with correct significant digits.

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.96QP: Hydrogen is an ideal fuel in many respects; for example, the product of its combustion, water, is...
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Calculate the energy of combustion per gram of Olive Oil (kJ/g) if 29.9 mL of water is placed in the test tube and the temperature changes from 22.9 °C to 44.6 °C. The initial mass of the spirit burner is 204.60 g and the final mass is 204.51g. State your answer with correct significant digits. Notes: Include a negative sign if the reaction is exothermic Do not include units in your answer.
Transcribed Image Text:Calculate the energy of combustion per gram of Olive Oil (kJ/g) if 29.9 mL of water is placed in the test tube and the temperature changes from 22.9 °C to 44.6 °C. The initial mass of the spirit burner is 204.60 g and the final mass is 204.51g. State your answer with correct significant digits. Notes: Include a negative sign if the reaction is exothermic Do not include units in your answer.
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