Calculate the electric dipole moment for the transition from the first excited stateY(10) to the ground stateY(20) 2:11 1 mi Yim, (0,0) 0 2√r √√Cos 0 1 1 √√(sin ei √√(3 cos² 0-1) 2 2 √√(cos sin )etio 2 +√(sin² 0¹24 2:15 k=1.3806x10 23 m n².kg.S².K Planck's constant = 6.6x10-34 Joule - sec Speed of light = 2.9×108 m/sec - u = 1.66×10-27 Kg 0 0 ±1 0 ±1 +2
Calculate the electric dipole moment for the transition from the first excited stateY(10) to the ground stateY(20) 2:11 1 mi Yim, (0,0) 0 2√r √√Cos 0 1 1 √√(sin ei √√(3 cos² 0-1) 2 2 √√(cos sin )etio 2 +√(sin² 0¹24 2:15 k=1.3806x10 23 m n².kg.S².K Planck's constant = 6.6x10-34 Joule - sec Speed of light = 2.9×108 m/sec - u = 1.66×10-27 Kg 0 0 ±1 0 ±1 +2
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Transcribed Image Text:Calculate the electric dipole
moment for the transition from
the first excited stateY(10) to
the ground stateY(20)
2:11
1
m₁
Yim, (0,0)
0
0
ztr
1
0
√cose
1
±1
2
0
2
±1
2
+2
Planck's constant =
F-1/2
(sin)eti
+√√(3 cos² 0-1)
F/1/1₁ (cosesin)eti
√(sin²
(sin² 0)*
1216
e
2:15
-23
m
n².kg.S¹².K
= 6.6x10-34 Joule-sec
Speed of light = 2.9×108 m/sec
u = 1.66×10-27 Kg
k=1.3806 x10
2:16 ✔
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