Calculate the discharge through the channel and the floodway (shown in the Figure below) for steady uniform flow, with S = 0.0009 and y = 8 ft. n=0.025 12 m 5 m n=0.040 [Σ, Pn] + Paper 120 m Side slopes 1:1 Use the following equivalent channel roughness formula due to Pavlovskii (1931)* ne = For 25,000 cfs flow through the channel above, find the depth of flow in the floodway when the slope of the energy grade line is 0.0004.
Calculate the discharge through the channel and the floodway (shown in the Figure below) for steady uniform flow, with S = 0.0009 and y = 8 ft. n=0.025 12 m 5 m n=0.040 [Σ, Pn] + Paper 120 m Side slopes 1:1 Use the following equivalent channel roughness formula due to Pavlovskii (1931)* ne = For 25,000 cfs flow through the channel above, find the depth of flow in the floodway when the slope of the energy grade line is 0.0004.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Calculate the discharge through the channel and the floodway (shown
in the Figure below) for steady uniform flow, with S = 0.0009 and
y = 8 ft.
n=0.025
12 m
5 m
n=0.040
POPSPAREN
[Σ, Pn]
+
120 m
Side
slopes
1:1
Use the following equivalent channel roughness formula due to Pavlovskii
(1931)*
ne =
For 25,000 cfs flow through the channel above, find the depth of flow
in the floodway when the slope of the energy grade line is 0.0004.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffd988327-d2ff-4971-a99e-bef2e7d2c1a8%2F0a1fd073-b452-471f-9c2a-96d262dd889a%2Ft8y2u3j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculate the discharge through the channel and the floodway (shown
in the Figure below) for steady uniform flow, with S = 0.0009 and
y = 8 ft.
n=0.025
12 m
5 m
n=0.040
POPSPAREN
[Σ, Pn]
+
120 m
Side
slopes
1:1
Use the following equivalent channel roughness formula due to Pavlovskii
(1931)*
ne =
For 25,000 cfs flow through the channel above, find the depth of flow
in the floodway when the slope of the energy grade line is 0.0004.
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