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Calculate the degree of unsaturation (DU) for a molecule with the formula of C5H12.

Calculate the degree of unsaturation (DU) for a molecule with the formula of C5H12.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Calculate the degree of unsaturation (DU) for a molecule with the formula of C₅H₁₂.** The degree of unsaturation, also known as the index of hydrogen deficiency (IHD), is a calculation used in organic chemistry to determine the total number of rings and multiple bonds in a compound. ### Formula for Degree of Unsaturation (DU): \[ \text{DU} = \frac{2C + 2 + N - X - H}{2} \] Where: - \( C \) = number of carbon atoms - \( H \) = number of hydrogen atoms - \( N \) = number of nitrogen atoms - \( X \) = number of halogens (F, Cl, Br, I) ### Calculation for C₅H₁₂: Substitute the given values into the formula: - \( C = 5 \) - \( H = 12 \) - \( N = 0 \) (not present) - \( X = 0 \) (not present) \[ \text{DU} = \frac{2(5) + 2 + 0 - 0 - 12}{2} = \frac{10 + 2 - 12}{2} = \frac{0}{2} = 0 \] ### Conclusion: The degree of unsaturation for the molecule with the formula C₅H₁₂ is 0, indicating that it is a saturated molecule with no rings or multiple bonds.
Transcribed Image Text:**Calculate the degree of unsaturation (DU) for a molecule with the formula of C₅H₁₂.** The degree of unsaturation, also known as the index of hydrogen deficiency (IHD), is a calculation used in organic chemistry to determine the total number of rings and multiple bonds in a compound. ### Formula for Degree of Unsaturation (DU): \[ \text{DU} = \frac{2C + 2 + N - X - H}{2} \] Where: - \( C \) = number of carbon atoms - \( H \) = number of hydrogen atoms - \( N \) = number of nitrogen atoms - \( X \) = number of halogens (F, Cl, Br, I) ### Calculation for C₅H₁₂: Substitute the given values into the formula: - \( C = 5 \) - \( H = 12 \) - \( N = 0 \) (not present) - \( X = 0 \) (not present) \[ \text{DU} = \frac{2(5) + 2 + 0 - 0 - 12}{2} = \frac{10 + 2 - 12}{2} = \frac{0}{2} = 0 \] ### Conclusion: The degree of unsaturation for the molecule with the formula C₅H₁₂ is 0, indicating that it is a saturated molecule with no rings or multiple bonds.
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