Calculate the daily efficiency of a single-phase joule with an output power of 350 kilovolts-ampere at full load. If the pulp and copper tissues at full pregnancy are equal 4.2 kW 3.2 kilowatts, respectively. If the transformer works during the hours of the day as follows: (1) Six hours at full load and has a factor of 0.85 lag. (ii) Three hours at three quarters of full load and treat capacity 0.8 late. (ii) A year of hours at a quarter of a full pregnancy and an amount of one is treated. (7) Four hours at one-fifth of the full pregnancy, and its amount is treated as one. (7) Five hours when not pregnant. e 8:52

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Calculate the daily efficiency of a
single-phase joule with an output power of
350 kilovolts-ampere at full load. If the pulp
and copper tissues at full pregnancy are equal
4.2 kW
3.2
kilowatts, respectively. If the transformer
works during the hours of the day as follows:
(1) Six hours at full load and has a factor of
0.85 lag. (ii) Three hours at three quarters of
full load and treat capacity
0.8 late. (ii) A year of hours at a quarter of
a full pregnancy and an amount of one is
treated. (7) Four hours at one-fifth of the full
pregnancy, and its amount is treated as one.
(7) Five hours when not pregnant.
2 8:52 /
Transcribed Image Text:Calculate the daily efficiency of a single-phase joule with an output power of 350 kilovolts-ampere at full load. If the pulp and copper tissues at full pregnancy are equal 4.2 kW 3.2 kilowatts, respectively. If the transformer works during the hours of the day as follows: (1) Six hours at full load and has a factor of 0.85 lag. (ii) Three hours at three quarters of full load and treat capacity 0.8 late. (ii) A year of hours at a quarter of a full pregnancy and an amount of one is treated. (7) Four hours at one-fifth of the full pregnancy, and its amount is treated as one. (7) Five hours when not pregnant. 2 8:52 /
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