Calculate the daily efficiency of a single-phase transformer with an output capacity of 350 kVA at full load. If the losses of core and copper at full load are equal to 4.2 kilowatts and 3.2 kilowatts, respectively. If the transformer operates during the day as follows i 6 hours at full load and at a factor of 0.85 lagging. Three hours at three quarters of the full pregnancy with a factor of 0.8 late (iii) Six hours at one quarter of the full pregnancy and with a factor of one. Four hours at one fifth of the full pregnancy and by a factor of one. Five hours when not pregnant.
Calculate the daily efficiency of a single-phase transformer with an output capacity of 350 kVA at full load. If the losses of core and copper at full load are equal to 4.2 kilowatts and 3.2 kilowatts, respectively. If the transformer operates during the day as follows i 6 hours at full load and at a factor of 0.85 lagging. Three hours at three quarters of the full pregnancy with a factor of 0.8 late (iii) Six hours at one quarter of the full pregnancy and with a factor of one. Four hours at one fifth of the full pregnancy and by a factor of one. Five hours when not pregnant.
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.26P: A bank of three single-phase transformers, each rated 30MVA,38.1/3.81kV, are connected in Y- with a...
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![Calculate the daily efficiency of a
single-phase transformer with an
output capacity of 350 kVA at full
load. If the losses of core and copper
at full load are equal to 4.2 kilowatts
and 3.2 kilowatts, respectively. If the
transformer operates during the day
as follows i 6 hours at full load and at
a factor of 0.85 lagging. Three hours
at three quarters of the full pregnancy
with a factor of 0.8 late (iii) Six hours
at one quarter of the full pregnancy
and with a factor of one. Four hours at
one fifth of the full pregnancy and by
a factor of one. Five hours when not
pregnant.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f0c5b6b-03a9-4afe-a216-36d2daf1abf0%2F343ff258-097d-487d-a4e1-08fd0d7db2c1%2Fasdw1k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculate the daily efficiency of a
single-phase transformer with an
output capacity of 350 kVA at full
load. If the losses of core and copper
at full load are equal to 4.2 kilowatts
and 3.2 kilowatts, respectively. If the
transformer operates during the day
as follows i 6 hours at full load and at
a factor of 0.85 lagging. Three hours
at three quarters of the full pregnancy
with a factor of 0.8 late (iii) Six hours
at one quarter of the full pregnancy
and with a factor of one. Four hours at
one fifth of the full pregnancy and by
a factor of one. Five hours when not
pregnant.
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