Calculate the change in internal energy (kJ/mol) when 4 moles of NHa(g) are moles of NO(g) at 4 atm. and 325°C. ANH,(g) + 50,(g) -- 4NO(g) + 6H;0(g) AH = -906 kJ/mol R= 0.0821 Latm/molK or 8.314 J/K-mol Select one: O- 91.80 O- 908.48 O- 909.31 O - 910.14 O- 910.97
Calculate the change in internal energy (kJ/mol) when 4 moles of NHa(g) are moles of NO(g) at 4 atm. and 325°C. ANH,(g) + 50,(g) -- 4NO(g) + 6H;0(g) AH = -906 kJ/mol R= 0.0821 Latm/molK or 8.314 J/K-mol Select one: O- 91.80 O- 908.48 O- 909.31 O - 910.14 O- 910.97
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![Calculate the change in internal energy (kJ/mol) when 4 moles of NHa(g) are
moles of NO(g) at 4 atm. and 325°C.
ANH,(g) + 50,(g) -- 4NO(g) + 6H;0(g)
AH = -906 kJ/mol
R= 0.0821 Latm/molK or 8.314 J/K-mol
Select one:
O- 91.80
O- 908.48
O- 909.31
O - 910.14
O- 910.97](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6636ddb9-ae86-4ad8-9a43-1a5f3a73ada3%2F14a8b804-c04f-4b9a-9e45-059a40ae5c42%2Fskqmlv1.png&w=3840&q=75)
Transcribed Image Text:Calculate the change in internal energy (kJ/mol) when 4 moles of NHa(g) are
moles of NO(g) at 4 atm. and 325°C.
ANH,(g) + 50,(g) -- 4NO(g) + 6H;0(g)
AH = -906 kJ/mol
R= 0.0821 Latm/molK or 8.314 J/K-mol
Select one:
O- 91.80
O- 908.48
O- 909.31
O - 910.14
O- 910.97
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