Calculate the cell potential of a cell operating with the following reaction at 25°C in which[Cr2O72] = 0.040 M ,I] = 0.025 M,[Cr**] = 0.10 M, and[H*] = 0.45 M.%3DCr2 O,2 (ag) + 6I (aq) + 14H+ (aq) → 2Cr³+ (aq) + 3I2 (s) + 7H2O(1)Standard Electrode (Reduction) Potentials in Aqueous Solution at 25°CCathode (Reduction)StandardHalf-ReactionPotential, E° (V)I2 (s) + 2e = 21 (aq)0.54Cr2 O,2 (aq) + 14H† (aq) + 6e¯ = 2Cr** (aq) + 7H2O(1) 1.33Cell potential =V The voltaic cellCd(s)|Cd²+ (aq) || Ni²+ (1.0 M)|Ni(s)has a cell potential of 0.320 V at 25°C. What is the concentration of cadmium ion? (E = 0.170 V.)'cellConcentration =MSubmit AnswerTry Another Version10 item attempts remaining

The electrochemical cell consists of two half-cell reactions where there is oxidation and reductions…

Calculate the cell potential of a cell operating with the following reaction at 25°C in which [Cr20,2] = 0.040 M, I]= 0.025 M, [c*+] = 0.10 M, and [H*] = 0.45 M. Cr20,2 (aq) + 6I (aq) + 14H* (aq) → 2Cr³* (aq) + 3I2(s) + 7H2O(1) Standard Electrode (Reduction) Potentials in Aqueous Solution at 25°C Cathode (Reduction) Half-Reaction Standard Potential, E° (V) I2 (s) + 2e¯= 21¯(aq) 0.54 Cr20,2 (aq) + 14H† (aq) + 6e¯ = 2Cr** (aq) + 7H2O(1) 1.33 Cell potential V

Calculate the cell potential of a cell operating with the following reaction at 25°C in which [Cr20,2] = 0.040 M, I]= 0.025 M, [c+] = 0.10 M, and [H] = 0.45 M. Cr20,2 (aq) + 6I (aq) + 14H* (aq) → 2Cr³* (aq) + 3I2(s) + 7H2O(1) Standard Electrode (Reduction) Potentials in Aqueous Solution at 25°C Cathode (Reduction) Half-Reaction Standard Potential, E° (V) I2 (s) + 2e¯= 21¯(aq) 0.54 Cr20,2 (aq) + 14H† (aq) + 6e¯ = 2Cr** (aq) + 7H2O(1) 1.33 Cell potential V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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