A session.masteringchemistry.come MasteringChemistry: Ch 9.7 to 9.10G Enter your answer using units of molar he.E Crayfish - Google Slides Masteringchemistry: Ch 9.7 to 9.10G Enter your answer using units of molar he.E Crayfish - Google Slidesb My Questions | bartlebyC The Table Below Contains The Bond Dl. View Available Hint(s)The table below contains the bond dissociationenergies for common bonds. The information can beused to calculate the energy needed to break all thebonds in a given molecule.HAO) E) ?DH,0D_H{ _2}O =ValueUnitsDissociation energy(kJ/mol )BondC-C350SubmitC-C611C-H410Part DC-O350C-0732Calculate the bond dissociation energy needed to break all the bonds in a mole of carbon dioxide, CO2O-0180Express your answer as an integer and include the appropriate units.O-0498> View Available Hint(s)H-O460?Dco,D_CO_2 = ValueUnitsSubmitMacBook Proesc&%#$78@56.342

Since you have posted multiple questions in a single session we are entitiled to answer only first question. if u get solved another questions please repost it on other session. Given: bond dissociation energy of the CH4 in CH4 molecule there are 4 C-H bonds. if we break the one bond C-H bond in CH4 we need 410 kJ/mol of energy. hence there are 4 C-H bonds. in a molecule. 4×410 kJ/mol = 1640 kJ/mol this is the bond dissociation energy for the CH4 molecule.

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Calculate the bond dissociation energy for the breaking of all the bonds in a mole of methane, CH4. Express your answer to four significant figures and include the appropriate units. > View Available Hint(s)

Calculate the bond dissociation energy for the breaking of all the bonds in a mole of methane, CH4. Express your answer to four significant figures and include the appropriate units. > View Available Hint(s)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Use the molar bond enthalpy data in the table to estimate Average molar bond enthalpies. (Hpond) the value of AHan for the equation Bond kJ. mol-1 Bond kJ. mol-1 CCI, (g) + 2F, (8) → CF,(g) + 2 CL,(g) O-H 464 C=N 890 0-0 142 N-H 390 The bonding in the molecules is shown. С-О 351 N-N 159 O=0 502 N=N 418 C=0 730 N=N 945 C CI С-С 347 F-F 155 C=C 615 Cl-CI 243 C=C 811 Br-Br 192 С-Н 414 H-H 435 C-F 439 H-F 565 C-Cl 331 H-CI 431 C-Br 276 H-Br 368 C-N 293 H-S 364 C=N | 615 S-S 225
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MISSED THIS? Read Section 7.6 (Pages 281- 284), Watch IWE 7.7 View Available Hint(s) Nitromethane (CH,NO2) burns in air to produce significant amounts of heat via the following reaction Hint 1. Calculate the number of moles of nitromethane 2CH,NO, (1) +O2(g)→ 2CO2(g) +3H,O(1) + N2(g) The value of AH is related to the balanced chemical equation by the number of moles of nitromethane. Calculate the number of moles of nitromethane in a 2.73-kg sample. AHn -1418 kJ Express your answer in moles. mol CH, NO2 44.72 Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Convert the mass of nitromethane from kg to g. Then use the molar mass of nitromethane as a conversion factor to obtain a value in mol HA Value Units = b
Use the molar bond enthalpy data in the table to estimate Average molar bond enthalpies. (Hpond) the value of AHn for the equation Bond kJ - mol-1 Bond kJ - mol-1 CCI, (g) + 2F, (g) CF,(g) + 2Cl, (g) O-H 464 C=N 890 The bonding in the molecules is shown. 0-0 142 N-H 390 С-О 351 N-N 159 CICI O=0 502 N=N 418 + C CI C=0 730 N=N 945 F-F С-С 347 F-F 155 C=C 615 Cl-CI 243 C=C 811 Br-Br 192 С-Н 414 Н-Н 435 C-F 439 Н-F 565 C-CI 331 Н-С 431 C-Br 276 Н-Br 368 C-N 293 H-S 364 C=N 615 S-S 225
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6. Estimate the enthalpy change for the following reaction. Show all your steps to get full credit. Include your units along with your numeric answer 2H2 (g) + N2 (g) à 2NH3 (g)
Use Table 9.4 to calculate an approximate enthalpy or heat of reaction for the combustion of one mole of methane gas (CH4) to form gaseous H₂O and CO₂. What Volume (in L) of methane is needed to produce 2715 kJ of heat for methane gas at 33 °C and 9.50 atm pressure? Hint given in feedback
Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2H₂O₂(1)→2H₂O(1) + O₂(g) ANSWER: Submit Answer [Review Topics] [References] Use the References to access important values if needed for this question. kJ Retry Entire Group 8 more group attempts remaining Cengage Learning Cengage Technical Support
General Chemistry 4th Edition McQuarrie • Rock Gallogly University Science Books presented by Macmillan Learning Bond kJ . mol-1 Bond kJ · mol-1 Use the molar bond enthalpy data in the table to estimate the value of AHan for the equation. 0-H 464 C=N 890 0-0 142 N-H 390 NH, (g) + 20,(g) → HNO,(g) + H,O(g) С-О 351 N-O 201 The bonding in the molecules is shown. O=0 502 N=N 418 C=0 730 N=O 607 H + С-С 347 F-F 155 С-С 615 Cl–Cl 243 C=C 811 Br-Br 192 С-Н 414 Н-Н 435 С-F 439 Н-F 565 C-CI 331 H-C1 431 С-Br 276 H-Br 368 С-N 293 H-S 364 C=N 615 S-S 225 kJ-mol-! Question Source: McQuarrie, Rock, And Gallogly 4e - General Chemsitry | Publisher: Universi
eats of formation given in the table: ! Formula C₂H2(g) 226.7 NH3(g) -46.19 C6H6(1) 49.0 ate CaCo3(s) -1207.1 -635.5 CaO(s) CO2(g) AH f (kJ/mol) ide CO(g) C(s) -393.5 -110.5 1.88 C₂H6(8) -84.68 C₂H5 OH (1) -277.7 C₂H4(8) 52.30 C6H12O6 -1273 Substance OA Hrxn = 327.6 kJ/mol OA Hrxn = -163.8 kJ/mol OAHrxn = -327.6 kJ/mol OA Hrxn = 56.1 kJ/mol OA Hrxn = 163.8 kJ/mol Hydrogen chloride Hydrogen fluoride Hydrogen iodide Methane Methanol Propane Silver chloride Sodium bicarbonate Sodium carbonate Sodium chloride Sucrose Water (s) nide HBr(g) -36.23 Water vapor :a, determine the enthalpy change for the reaction: 2 CH4(g) + O₂(g) 2 CH3OH(e) Formula AH f (kJ/mol) HCI(g) HF(g) HI(g) 25.9 CH4(g) -74.80 |CH3 ОН -238.6 (1) C3H8(g) -103.85 -127.0 AgCl(s) NaHCO3 (s) C12H22O11130.9 (s) NaCl -92.30 -268.60 -947.7 -410.9 C12H22O11221 (s) H₂O(l) -285.8 H₂O(g) -241.8
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