a. How many non-polar and polar bonds are in the reactants? b. How many non-polar and polar bonds are in the products? c. What is the change in enthalpy (AH) for this reaction (positive or negative)? What is the evidence for your response? d. What is the change in entropy (AS) for this reaction (positive or negative)? What is your evidence for your response?
a. How many non-polar and polar bonds are in the reactants? b. How many non-polar and polar bonds are in the products? c. What is the change in enthalpy (AH) for this reaction (positive or negative)? What is the evidence for your response? d. What is the change in entropy (AS) for this reaction (positive or negative)? What is your evidence for your response?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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please do a,c,d.
and a , about the Br-Br bond it should have a total of 5 bonds on the reactant side.
For C, look at the number of polar/nonpolar bonds to decide enthalpy. For D, use the total number of molecules on each side.
Transcribed Image Text:5. For the chemical reaction below (please note, this is the same as CH4 + Br2 → CH3Br
+ HBr; the Br2 over the arrow is a reactant. Let me know if you have any questions
about this):
a. How many non-polar and polar bonds are in the reactants?
b. How many non-polar and polar bonds are in the products?
c. What is the change in enthalpy (AH) for this reaction (positive or negative)? What is
the evidence for your response?
d. What is the change in entropy (AS) for this reaction (positive or negative)? What is
your evidence for your response?
e. Is this reaction exergonic (spontaneous) or endergonic (nonspontaneous)?
f. Is the carbon in this reaction being reduced or oxidized? What evidence do you have
for your claim?
H
H-CH-
H
Br₂
hv
H
H-C-Br +
-Br + HBr
H
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