Calculate the axial and total angular momentum of the Earth.
Q: meteoroid is moving towards a planet. It has mass m = 0.18×109 kg and speed v1 = 4.7×107 m/s at…
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A: The mass of each star is m=7.2x1030 kg. The orbtal radius is r=6.4x1011 m. The mass of the central…
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Q: 4. Sphere A has mass ma = 0.06 kg, velocity magnitude va - 3.0 m/s making = an angle 25° with the +…
A: ma = 0.06 kg va = 3 m/s θa = 25omb = 0.04 kg vb = 4 m/s along +y axis mc = 0.05 kg vc = 5 m/s along…
Q: An object is dropped from an altitude of one Earth radius above Earth's surface. If M is the mass of…
A: Given :Altitude of object = RTotal distance = altitude + radius of EarthTotal distance = 2RMass of…
Q: A meteoroid is moving towards a planet. It has mass m=0.54×109 kg and speed v1=4.7×107 m/s at…
A: thank you
Q: planet’s
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Q: (a) The distance between the Earth and the Moon (center to center) is approximately 239,000 miles.…
A: Part-(a) Given data: The distance between the Earth and the Moon is d=239000 miles. The mass of the…
Q: A shuttle is being launched off a planet that has no air. The planet has a radius of 3.46×106 m and…
A: Given information:The mass of the planet (M) = 3.60 × 1024 kgThe radius of the planet (R) = 3.46 ×…
Q: In the year 8000 (Y8K) the mass of the Earth has increased (due to excessive space mining). As a…
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Q: A certain triple-star system consists of two stars, each of mass m = 6.7×1030 kg, revolving in the…
A: As force between the orbiting stars is very less than the force between the central star and the…
Q: The 0.100 kg sphere in (Figure 1) is released from rest at the position shown in the sketch, with…
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Q: what will be its velocity when it reaches 5.2x10^6m from the center of the new planet?
A: Principle of Conservation of Energy According to the law of conservation energy, energy can neither…
Q: Stars and black holes in a binary system orbit each other in circular orbits of radius r1 and r2…
A: mass of an orbital m= 1.98x1030 kg v1 =5.36 times faster than our Sun T=30 hours r1=?,r2=?m2=?
Q: NOTE: Your answer suggests that you have assumed constant gravitational
A: Explained as, F=-GMMR+y2
Q: Three uniform spheres of masses m1 = 3.00 kg, m2 = 4.00 kg, and m3 = 6.50 kg are placed at the…
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Q: a)Enter an expression for the total energy E of the meteoroid at R, the surface of the planet, in…
A: Given that mass of the meteoroid and mass of the planet and distance from the center of the planet…
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Q: The figure below shows a spherical hollow inside a lead sphere of radius R = 4.00 cm. The surface of…
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Q: Three uniform spheres of masses m₁ = 3.00 kg, m₂ = 4.00 kg, and m3 = 5.00 kg are placed at the…
A: FINAL ANSWER: Resultant gravitational force on the object of mass m2 is 8.34×10^-11i…
Q: The gas-giant planet Rom (mass 5.7⨯1026 kg) goes around the star Galla (mass 2.0⨯1030 kg) in a…
A: Part (i) The centripetal force for circular motion of Rom around Galla is provided by, Here M is…
Q: eteoroid’s speed at the planet’s surface, in terms of G, M, v1, R1, and R.
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Q: Hunting a black hole. Observations of the light from a certain star indicate that it is part of a…
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Q: Consider a planet that has two layers. There is a core, which has density 9.9 x 103 kg/m3 and…
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Q: During a solar eclipse, the Moon is positioned directly between Earth and the Sun. The masses of the…
A: Given Data Mass of the Sun is Msun=1.99×1030 kg Mass of the Earth is Mearth=5.98×1024 kg Mass of the…
Earth is rotating about the Sun in our solar system. The distance between the Earth and Sun is 1.5 × 10^11m. Consider the impact of an asteroid of mass 8.9 ×10^15 kg and a speed of 90,000 km/h with respect to the Earth’s surface. The asteroid strikes the Earth at the equator as shown in Figure. Consider the mass and radius of the Earth are ME = 5.97 × 10^24 kg and RE = 6.38×10^6 m, respectively. Assume that the axial and orbital axis of rotations are parallel to each other. Calculate the axial and total

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- A meteoroid is moving towards a planet. It has mass m = 0.22×109 kg and speed v1 = 3.5×107 m/s at distance R1 = 2.9×107 m from the center of the planet. The radius of the planet is R = 0.46×107 m. The mass of the planet is M = 3.2×1025 kg. There is no air around the. Calculate the value of v in meters per second.Planet X is a sphere where a 0.5 kg block weighs 36 N when sitting on the surface. If an object is dropped from rest at a distance 9R from X's center it is observed to impact the surface at a speed of 16,000 m/s. Find a value for the radius of planet X.A meteoroid is moving towards a planet. It has mass m = 0.54×109 kg and speed v1 = 4.7×107 m/s at distance R1 = 1.6×107 m from the center of the planet. The radius of the planet is R = 0.78×107 m. The mass of the planet is M = 5.6×1025kg. There is no air around the planet. a)Enter an expression for the total energy E of the meteoroid at R, the surface of the planet, in terms of defined quantities and v, the meteoroid’s speed when it reaches the planet’s surface. Select from the variables below to write your expression. Note that all variables may not be required.α, β, θ, d, g, G, h, m, M, P, R, R1, t, v, v1 b)Enter an expression for v, the meteoroid’s speed at the planet’s surface, in terms of G, M, v1, R1, and R. c)Calculate the value of v in meters per second.
- Can you please help me with this question please? I appreciate your help!Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject material as high as 500 km (or even higher) above the surface. Io has a mass of 8.93×1022kg8.93×1022kg and a radius of 1821 km. How high would this material go on earth if it were ejected with the same speed as on Io? (RE = 6370 km, mE=5.96×1024kg)Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is v| = 225 km/s and the orbital period of each is 11.6 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 x 1030 kg.) M XCM M Part 1 of 3 - Conceptualize From the given data, it is difficult to estimate a reasonable answer to this problem without working through the details and actually solving it. A reasonable guess might be that each star has a mass equal to or slightly larger than our Sun because fourteen days is short compared to the periods of all the Sun's planets. Part 2 of 3 - Categorize The only force acting on each star is the central gravitational force of attraction which results in a centripetal acceleration. When we solve Newton's second law, we can find the unknown mass in terms of the variables…
- Truck suspensions often have "helper springs" that engage at high loads. One such arrangement is a leaf spring with a helper coil spring mounted on the axle, as shown in the figure below. When the main leaf spring is compressed by distance y0, the helper spring engages and then helps to support any additional load. Suppose the leaf spring constant is 5.50 ✕ 105 N/m, the helper spring constant is 3.40 ✕ 105 N/m, and y0 = 0.500 m. A side view of a truck suspension. The truck body is above the wheel. The main leaf spring spans the horizontal width of the wheel and is attached at both ends to the truck body. The "helper" spring is aligned vertically with its lower end attached to the axle and the upper end unattached. The upper end is a distance y0 from the truck body. (a) What is the compression of the leaf spring for a load of 5.50 ✕ 105 N? (b) How much work is done in compressing the springs?Scientists have discovered a distant planet with a mass of 8.2x1023 kg. The planet has a small moon that orbits with a period of 6 hours and 36 minutes. Use only this information (and the value of G) to calculate the radius of the moon's orbit (in units of 106 m).The figure shows a spherical hollow inside a lead sphere of radius R = 4.8 m; the surface of the hollow passes through the center of the sphere and “touches” the right side of the sphere. The mass of the sphere before hollowing was M = 255 kg. With what gravitational force does the hollowed-out lead sphere attract a small sphere of mass m = 10 kg that lies at a distance d = 13 m from the center of the lead sphere, on the straight line connecting the centers of the spheres and of the hollow?
- A meteoroid is moving towards a planet. It has mass m = 0.18×109 kg and speed v1 = 3.8×107 m/s at distance R1 = 1.6×107 m from the center of the planet. The radius of the planet is R = 0.26×107 m. The mass of the planet is M = 10×1025 kg. There is no air around the planet. a)Enter an expression for the total energy E of the meteoroid at R, the surface of the planet, in terms of defined quantities and v, the meteoroid’s speed when it reaches the planet’s surface. b)Enter an expression for v, the meteoroid’s speed at the planet’s surface, in terms of G, M, v1, R1, and R. c)Calculate the value of v in meters per second.A binary-star system contains a visible star and a black hole moving around their center of mass in circular orbits with radii r1 and r2 , respectively. The visible star has an orbital speed of v=5.36x105 ms-1 and a mass of m1 =5Ms ,where Ms= 1.98x1030kg is the mass of our Sun. Moreover, the orbital period of the visible star is T = 30 hours.(a) What is the radius r1 of the orbit of the visible star?(b) Calculate the mass m2 of the black hole in terms of MS . [Hint: One root of the equation x3 = 20a(5a+x)2 , where a is a constant, is x = 28a .]The centers of the earth and its moon are separated by an average of 3.84 c 10^5 m and the moon's mass is 7.35 c 10^22 kg. What does Earth's moon exert on a 10 kg mass?