Calculate the amount of heat required for the vaporization of 3.80 kg at 45∘C. Given that latent heat of vaporization is 2.3×105J/kg and specific heat capacity of water is 4190J/kg∘C.
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Calculate the amount of heat required for the vaporization of 3.80 kg at 45∘C. Given that latent heat of vaporization is 2.3×105J/kg and specific heat capacity of water is 4190J/kg∘C.
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- In the laboratory, calorimetry can be used to determine the latent heat of fusion of water, LfLf. If an ice cube of mass 30.0g30.0g at 0∘C0∘C is added to a calorimeter cup of mass mc=60.0gmc=60.0g that contains water of mass 170g170g at an initial temperature TiwTiw of 20∘C20∘C, after the ice melts, the final temperature of the water TfwTfw is found to be 5.57∘C5.57∘C. Based on this data, what is the latent heat of fusion of water? The specific heat capacities of water and the calorimeter are 4186J/(kg.K)4186J/(kg.K) and 900J/(kg.K)900J/(kg.K), respectivelyA liquid food (density = 1,010 kg/m3, k =.5W/m°C, Cp = 3,000J/kg°C) is being heatedfrom an initial temperature of 12°C to a final center temperature. The heating occurs in a cylindrical container (D = .07 m, L =.10 m) and the heating conditions are: heating temperature of 121°C and convective heat transfer coefficient of1W/m2°C. a)Calculate the final product temperature at the center after heating for 30 minutes(1800 s). b)Is heating time sufficient to reach target center temperature of 65°C?Suppose you want to raise the temperature of a 0.185-kg piece of ice from -20.0°C to 130°C. The heat of fusion is Lf = 334 kJ/kg, and the heat of vaporization is Lv = 2256 kJ/kg. In this problem, take 1520 J/kg⋅°C as the specific heat of steam, and 2090 J/kg⋅°C as the specific heat of ice. Part (a) How much heat, in kilocalories, must be transferred for this to happen, including the energy needed for phase changes? Part (b) How much time, in seconds, is required to do this, assuming a constant 20.0 kJ/s rate of heat transfer?
- Estimate the temperature change you expect in this air. Let the volume of your room be 38 m3. Heat capacity of air is 1000 J/kg⋅∘C.Ice at 0 °C is placed in a Styrofoam cup containing 0.62 kg of lemonade at 32 °C. The specific heat capacity of lemonade is virtually the same as that of water; that is, c = 4180 J/(kg C°). After the ice and lemonade reach an equilibrium temperature, some ice still remains. The latent heat of fusion for water is Lf = 3.35 x 105 J/ kg. Assume that the mass of the cup is so small that it absorbs a negligible amount of heat, and ignore any heat lost to the surroundings. Determine the mass of ice that has melted, in grams.A 235-g sample of a substance is heated to 350 ∘C and then plunged into a 105-g aluminum calorimeter cup containing 185 gg of water and a 17-g glass thermometer at 11.5 ∘C. The final temperature is 35.0∘C. The value of specific heat for aluminium is 900 J/kg⋅C , for glass is 840 J/kg⋅C, and for water is 4186 J/kg⋅C∘ What is the specific heat of the substance? (Assume no water boils away.)