Calculate the AG for the cell: Cu(s)|Cu*2 (0.010 M)|| Ag*(0.050 M)|Ag(s).E°Cu| Cu+2 = 0.337 VAg | Ag+= 0.799 V-85.7 kJ-87.4 kJ-89.2 kJ-92.6 kJ

Here we are calculating Gibbs energy from electrode potential

Calculate the AG for the cell: Cu(s)|Cu*2 (0.010 M)|| Ag*(0.050 M)|Ag(s). ɛ°C Cu Cu+2 = 0.337 V ɛ° Ag | Ag+ = 0.799 V %3D %3D -85.7 kJ -87.4 kJ -89.2 kJ -92.6 kJ

Calculate the AG for the cell: Cu(s)|Cu2 (0.010 M)|| Ag(0.050 M)|Ag(s). ɛ°C Cu Cu+2 = 0.337 V ɛ° Ag | Ag+ = 0.799 V %3D %3D -85.7 kJ -87.4 kJ -89.2 kJ -92.6 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Calculate the AG for the cell: Cu(s)|Cu*2 (0.010 M)|| Ag*(0.050 M)|Ag(s).
E°Cu| Cu+2 = 0.337 V
Ag | Ag+
= 0.799 V
-85.7 kJ
-87.4 kJ
-89.2 kJ
-92.6 kJ

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