Calculate the 95% margin of error in estimating a population mean μ for the following values. (Round your answer to three decimal places.) n = 20, ² = 64

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Calculate the 95% margin of error in estimating a population mean \( \mu \) for the following values. (Round your answer to three decimal places.)

\[ n = 20, \ s^2 = 64 \]

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Transcribed Image Text:Calculate the 95% margin of error in estimating a population mean \( \mu \) for the following values. (Round your answer to three decimal places.) \[ n = 20, \ s^2 = 64 \] [Input box for answer]
Calculate the 95% margin of error in estimating a population mean \( \mu \) for the following values. (Round your answer to three decimal places.)

\[ n = 30, \, \sigma^2 = 3.9 \]

\[_\_\_\_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_\_\_\_ \]

Consider that for \( n = 30 \) and \( \sigma^2 = 0.1, \, \sigma^2 = 1.0, \) and \( \sigma^2 = 1.7 \) the margins of error are 0.113, 0.358, and 0.467 respectively. Comment on how a larger population variance affects the margin of error.

- ( ) As the population variance \( \sigma^2 \) increases, the margin of error decreases.
- ( ) As the population variance \( \sigma^2 \) increases, the margin of error remains relatively constant.
- ( ) As the population variance \( \sigma^2 \) increases, the margin of error also increases.
Transcribed Image Text:Calculate the 95% margin of error in estimating a population mean \( \mu \) for the following values. (Round your answer to three decimal places.) \[ n = 30, \, \sigma^2 = 3.9 \] \[_\_\_\_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_\_\_\_ \] Consider that for \( n = 30 \) and \( \sigma^2 = 0.1, \, \sigma^2 = 1.0, \) and \( \sigma^2 = 1.7 \) the margins of error are 0.113, 0.358, and 0.467 respectively. Comment on how a larger population variance affects the margin of error. - ( ) As the population variance \( \sigma^2 \) increases, the margin of error decreases. - ( ) As the population variance \( \sigma^2 \) increases, the margin of error remains relatively constant. - ( ) As the population variance \( \sigma^2 \) increases, the margin of error also increases.
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