Calculate the 95% margin of error in estimating a population mean μ for the following values. (Round your answer to three decimal places.) n = 20, ² = 64
Calculate the 95% margin of error in estimating a population mean μ for the following values. (Round your answer to three decimal places.) n = 20, ² = 64
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![Calculate the 95% margin of error in estimating a population mean \( \mu \) for the following values. (Round your answer to three decimal places.)
\[ n = 20, \ s^2 = 64 \]
[Input box for answer]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbff43673-f06b-43ca-b409-46eb420ace6b%2F6fcd01bc-a5de-4233-8c7a-4a8718da5e26%2Fhbfgs5v_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the 95% margin of error in estimating a population mean \( \mu \) for the following values. (Round your answer to three decimal places.)
\[ n = 20, \ s^2 = 64 \]
[Input box for answer]
![Calculate the 95% margin of error in estimating a population mean \( \mu \) for the following values. (Round your answer to three decimal places.)
\[ n = 30, \, \sigma^2 = 3.9 \]
\[_\_\_\_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_\_\_\_ \]
Consider that for \( n = 30 \) and \( \sigma^2 = 0.1, \, \sigma^2 = 1.0, \) and \( \sigma^2 = 1.7 \) the margins of error are 0.113, 0.358, and 0.467 respectively. Comment on how a larger population variance affects the margin of error.
- ( ) As the population variance \( \sigma^2 \) increases, the margin of error decreases.
- ( ) As the population variance \( \sigma^2 \) increases, the margin of error remains relatively constant.
- ( ) As the population variance \( \sigma^2 \) increases, the margin of error also increases.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbff43673-f06b-43ca-b409-46eb420ace6b%2F6fcd01bc-a5de-4233-8c7a-4a8718da5e26%2F1oi833_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the 95% margin of error in estimating a population mean \( \mu \) for the following values. (Round your answer to three decimal places.)
\[ n = 30, \, \sigma^2 = 3.9 \]
\[_\_\_\_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_\_\_\_ \]
Consider that for \( n = 30 \) and \( \sigma^2 = 0.1, \, \sigma^2 = 1.0, \) and \( \sigma^2 = 1.7 \) the margins of error are 0.113, 0.358, and 0.467 respectively. Comment on how a larger population variance affects the margin of error.
- ( ) As the population variance \( \sigma^2 \) increases, the margin of error decreases.
- ( ) As the population variance \( \sigma^2 \) increases, the margin of error remains relatively constant.
- ( ) As the population variance \( \sigma^2 \) increases, the margin of error also increases.
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