NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Consider the statement that min(a, min(b, c) = min(min(a, b), c) whenever a, b, and care real numbers. Click and drag the steps to prove min(a, min(b, c)) = min(min(a, b). c) whenever a, b, and care real numbers. Assume a is the smallest real number. (Note: In your proof, consider the left side of the equation first.) (You must provide an answer before moving to the next part.) On the right-hand side, min(a, c) = a. On the right-hand side, min(a, b) is a, and therefore min(min(a, b), c) = min(a, c). So, the left-hand side equals a. On the right-hand side, min(b, c) = a. It follows that a ≥ min(b, c). It follows that a s min(b, c). Suppose a is the smallest of the three real numbers.
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Consider the statement that min(a, min(b, c) = min(min(a, b), c) whenever a, b, and care real numbers. Click and drag the steps to prove min(a, min(b, c)) = min(min(a, b). c) whenever a, b, and care real numbers. Assume a is the smallest real number. (Note: In your proof, consider the left side of the equation first.) (You must provide an answer before moving to the next part.) On the right-hand side, min(a, c) = a. On the right-hand side, min(a, b) is a, and therefore min(min(a, b), c) = min(a, c). So, the left-hand side equals a. On the right-hand side, min(b, c) = a. It follows that a ≥ min(b, c). It follows that a s min(b, c). Suppose a is the smallest of the three real numbers.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please help me with these two questions. I don't understand what to do.
Transcribed Image Text:NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Consider the statement that min(a, min(b, c))= min(min(a, b), c) whenever a, b, and care real numbers.
Click and drag the steps to prove min(a, min(b, c)) = min(min(a, b), c) whenever a, b, and c are real numbers. Assume a is the smallest
real number.
(Note: In your proof, consider the left side of the equation first.)
(You must provide an answer before moving to the next part.)
On the right-hand side, min(a, c) = a.
On the right-hand side, min(a, b) is a, and
therefore min(min(a, b), c) = min(a, c).
So, the left-hand side equals a.
On the right-hand side, min(b, c) = a.
It follows that a ≥ min(b, c).
It follows that a ≤ min(b, c).
Suppose a is the smallest of the three real
numbers.
Transcribed Image Text:NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Consider the statement that min(a, min(b, c)) = min(min(a, b), c) whenever a, b, and care real numbers.
Click and drag the steps to prove min(a, min(b, c)) = min(min(a, b), c) whenever a, b, and care real numbers. Assume b is the smallest
real number.
(Note: In your proof, consider the left side of the equation first.)
(You must provide an answer before moving to the next part.)
So, the left-hand side equals b.
on the right-hand side, min(a, b) = b, so,
min(min(a, b), c) = min(b, c).
It follows that b≥ min(a, c). Thus, min(b, c) = c.
Suppose b is the smallest of the three real
numbers.
On the right-hand side, min(b, c) = b.
It follows that b ≤ min(b, c). Thus, min(a, b) = b.
On the left-hand side, min(b,c) = c.
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