Calculate K if the equilibrium concentrations are 0.200M for H,S, 0.0100M for H,0, 0.230M for O, and 0.400M for SO2. Use the following balanced equation 2H2S(3) + 302(g) 2H2O + 2502ig

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**Calculating the Equilibrium Constant (K)**

To calculate the equilibrium constant (K) given the equilibrium concentrations, follow these steps. The equilibrium concentrations provided are:

- Hydrogen sulfide (\( \text{H}_2\text{S} \)): 0.200 M
- Water (\( \text{H}_2\text{O} \)): 0.0100 M
- Oxygen (\( \text{O}_2 \)): 0.230 M
- Sulfur dioxide (\( \text{SO}_2 \)): 0.400 M

We will use the following balanced equation for the calculation:

\[ 2\text{H}_2\text{S(g)} + 3\text{O}_2\text{(g)} \rightarrow 2\text{H}_2\text{O(g)} + 2\text{SO}_2(\text{g}) \]

### Step-by-Step Calculation:
1. Write the expression for the equilibrium constant, \( K \):
\[ K = \frac{[\text{H}_2\text{O}]^2 [\text{SO}_2]^2}{[\text{H}_2\text{S}]^2 [\text{O}_2]^3} \]

2. Substitute the given equilibrium concentrations into the expression:
\[ K = \frac{(0.0100)^2 (0.400)^2}{(0.200)^2 (0.230)^3} \]

3. Calculate the value of \( K \):
\[ K = \frac{(0.0001) (0.16)}{(0.04) (0.012167)} \]

\[ K = \frac{0.000016}{0.00048668} \]

\[ K \approx 0.03287 \]

So, the equilibrium constant \( K \approx 0.03287 \).

**Note:** The given text box with the label "Drag n' Drop here or Browse" seems to be an input section likely intended for users to upload files or additional data. 

This explanation would help students understand the process of determining the equilibrium constant with given equilibrium concentrations using a balanced chemical equation.
Transcribed Image Text:**Calculating the Equilibrium Constant (K)** To calculate the equilibrium constant (K) given the equilibrium concentrations, follow these steps. The equilibrium concentrations provided are: - Hydrogen sulfide (\( \text{H}_2\text{S} \)): 0.200 M - Water (\( \text{H}_2\text{O} \)): 0.0100 M - Oxygen (\( \text{O}_2 \)): 0.230 M - Sulfur dioxide (\( \text{SO}_2 \)): 0.400 M We will use the following balanced equation for the calculation: \[ 2\text{H}_2\text{S(g)} + 3\text{O}_2\text{(g)} \rightarrow 2\text{H}_2\text{O(g)} + 2\text{SO}_2(\text{g}) \] ### Step-by-Step Calculation: 1. Write the expression for the equilibrium constant, \( K \): \[ K = \frac{[\text{H}_2\text{O}]^2 [\text{SO}_2]^2}{[\text{H}_2\text{S}]^2 [\text{O}_2]^3} \] 2. Substitute the given equilibrium concentrations into the expression: \[ K = \frac{(0.0100)^2 (0.400)^2}{(0.200)^2 (0.230)^3} \] 3. Calculate the value of \( K \): \[ K = \frac{(0.0001) (0.16)}{(0.04) (0.012167)} \] \[ K = \frac{0.000016}{0.00048668} \] \[ K \approx 0.03287 \] So, the equilibrium constant \( K \approx 0.03287 \). **Note:** The given text box with the label "Drag n' Drop here or Browse" seems to be an input section likely intended for users to upload files or additional data. This explanation would help students understand the process of determining the equilibrium constant with given equilibrium concentrations using a balanced chemical equation.
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