Calculate Ig and VCE for the circuit in Figure 5-16 using the approximationsVE = -1 V and Ic = IE.FIGURE 5-16Vcc+15 VRc4.7 kNRB47 kNRE10 kNVEE-15 VonVE = -1 V- VEE -1 V -(-15 V) – 1 VRE14 V1.4 mA!!%3D10 k210 k2Vc = Vcc – IcRc = +15 V – (1.4 mA)(4.7 kN) = 8.4 V%3DVCE = 8.4 V – (-1) = 9.4 VActivate WinGo to Settings toemIf VEE is changed to -12 V, what is the new value of VCE?

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Calculate Ig and VCE for the circuit in Figure 5-16 using the approximations VE = -1 V and Ic = IE. FIGURE 5-16 Vcc +15 V Rc 4.7 kN RB 47 k2 RE 10 k2 VEE -15 V VE = -1 V - VEE – 1 V_ -(-15 V) – 1 V 14 V 1.4 mA %3D RE 10 kN 10 k2 Vc = Vcc – ICRC = +15 V – (1.4 mA)(4.7 kN) = 8.4 V VCE = 8.4 V - (-1) = 9.4 V Activate Win Go to Settings to If VEE is changed to -12 V, what is the new value of VCE?

Calculate Ig and VCE for the circuit in Figure 5-16 using the approximations VE = -1 V and Ic = IE. FIGURE 5-16 Vcc +15 V Rc 4.7 kN RB 47 k2 RE 10 k2 VEE -15 V VE = -1 V - VEE – 1 V_ -(-15 V) – 1 V 14 V 1.4 mA %3D RE 10 kN 10 k2 Vc = Vcc – ICRC = +15 V – (1.4 mA)(4.7 kN) = 8.4 V VCE = 8.4 V - (-1) = 9.4 V Activate Win Go to Settings to If VEE is changed to -12 V, what is the new value of VCE?

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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