Hey, I submitted this question today and I received a wrong answer from the company. Could I have another possible another to this question. ---**Question 6 of 10**Calculate the following derivative if \( y(t) = 6t^{-3} + 4t^2 \).(Use symbolic notation and fractions where needed.)\[\left. \frac{d^2y}{dt^2} \right|_{t=3} = \text{[blank for answer]}\]---**Explanation:**To solve this problem, perform the following steps:1. **First Derivative (\(\frac{dy}{dt}\)):** - Differentiate \( y(t) = 6t^{-3} + 4t^2 \) with respect to \( t \). 2. **Second Derivative (\(\frac{d^2y}{dt^2}\)):** - Differentiate the first derivative to find the second derivative. 3. **Evaluate at \( t = 3 \):** - Substitute \( t = 3 \) into the second derivative to find the specific value.Use symbolic notation and fractions as necessary to express the final answer. **Title: Calculating the Second Derivative of a Function****Objective:** To calculate the second derivative of the function \( y(t) = 6t - 3 \) with respect to \( t \).**Step-by-Step Solution:**1. **First Derivative:** \[ \frac{dy}{dt} = \frac{d}{dt} (6t - 3) \] \[ = 6 \] Since the derivative of a constant is zero and the derivative of \( 6t \) with respect to \( t \) is 6, the first derivative is 6.2. **Second Derivative:** \[ \frac{d^2y}{dt^2} = \frac{d}{dt} \left(6\right) \] \[ = 0 \] Since the derivative of a constant (6) is zero, the second derivative is zero.3. **Evaluating the Second Derivative at \( t = 3 \):** \[ \frac{d^2y}{dt^2} \bigg|_{t=3} = 0 \] The second derivative evaluated at \( t = 3 \) is 0. The boxed result on the page shows a numerical value of 8.296, but given the context of these calculations, this seems to be incorrect for the function calculated here. The correct calculation following the derivatives would result in zero.**Conclusion:** The process of differentiating involves finding the rate of change. In this example, finding both the first and second derivatives of \( y(t) = 6t - 3 \) demonstrates that the second derivative is zero, reflecting no change in the gradient of the linear function.

Given: yt=6t-3+4t2Aim: To find the value of d2ydt2t=3 . Basic information: ddxaxn = anxn-1

Answered: Calculate following derivative if y(t)…

Calculate following derivative if y(t) = 6t-3 + 412. (Use symbolic notation and fractions where needed.) d²y dt2 It=3

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

Similar questions

In my homework these options were marked as wrong. Could there be another way to match these options?
For this problem, assume the test had 6 true-false questions and 8 multiple-choice questions, and that each multiple-choice question had 5 choices. How many different answer sheets can be submitted?
You and 3 friends are moving into a 4-bedroom house and need to decide who gets which room. How many different ways could you and your friends assign the rooms? (Enter your answer as a whole number.)
Suppose your school has 1000 students. Why can you be pretty sure that some pair of them will have telephone numbers that end in the same two digits and that they will like the same brand of soda?
What do you think is the best way of sorting out these type of questions. When I'm studying I somehow always mix up negative and positive values or get something off somehow. so that I get one part wrong which leads to getting another part wrong and so on. I understand the concept of elimination and subsition but I can't seem to carry it out very well.
Unfortunately, for some reason, at least one of the answers isn't correct. I got the same answeres myself. Is there a reason any could be wrong?
That is the first answer I got and it was also marked as incorrect. I am not sure why. I also tried the rounded version and it didn't work.