Calculate ΔSvap for hydrogen sulfide from the following data: normal boiling point of H2S: -60.7oC ΔHvap of H2S: 18.7 kJ/mol Place ΔSvap in units of J/(mol K) and your answer should have 3 significant figures.

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A: Formula used :     Tb = delta H/ delta S

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A: Given , Initial temperature , T1=23.0°C=(23+273)K=296 KVapor pressure , P1 = 92.0 torrFinal…

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A: Given ∆H° = 38 kj/mol         = 38000j/mol. ∆S° = 113j/mol. Tb = ? ( Boiling point)

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Q: None

A: Step 1: Find the standard entropy of formation (T=298 K) for each product and reactant. Use the…

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Q: a) How much energy is needed to warm a 50.g ice cube at -15oC up to gas vapor at 115oC (all at…

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A: Entropy change can be given by deltaS = deltaHvap/Tb deltaHvap = Heat of vaporization Tb = boiling…

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A: Given, P1= 92 torrT1=23°C =(23+273)K=296 KP2=231.0 torrT2=45°C =(45+273)K=318 K

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Q: A compound melts at -55 ∘C and has a heat of fusion of 21 kJ/mol.  Calculate its change in entropy…

A: Melting point = -55°CT = (-55 + 273.15) K = 218.15 KHeat of Fusion = 21 kJ/mole = ∆H

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Q: AvapH = 47 kJ/mol AvapS = 121 J/K.mol

A:

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Q: What is true about 02 (g) + 2HCl (g) AHY-48 kJ mol i. The reaction is non-spontaneous. ii. The…

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A: Calculate entropy of vaporization of Pb: 1 kJ = 1000 J

Q: For mercury, Hg, the heat of fusion at its normal melting point of -39 °C is 2.3 kJ/mol. The…

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Q: Calculate ΔSvap for hydrogen sulfide from the following data: normal boiling point of H2S: -60.7oC…

A: ∆Svap = ∆Hvap / T  T = 273 - 60.7 = 212.3 K  ∆Hvap = 18.7 kJ = 18700 J