Calculate Hrxnfor the reaction:2H2O(l) 2H2(g) + O2(g)Use the following information:H2O(g) H2O(l) Hrxn= -45 kJ2H2O(g) 2H2(g) + O2(g)Hrxn= +480 kJA.+570 kJB.+525 kJC.+435 kJD.+390 kJ Calculate AHxn for the reaction:2H,0(1) → 2H2(g) + O2(g)Use the following information:H,0(g) → H,0(I)AHxn = -45 kJ2H,0(g) → 2H,(g) + O2(g)AHyn = +480 kJ%3DrxnА.+570 kJВ.+525 kJС.+435 kJD.+390 kJ

Answered: Image /qna-images/answer/6876bc0b-542d-4509-afcf-9f269257190c.jpg

Calculate AHxn for the reaction: 2H,0(1) → 2H2(g) + O2(g) Use the following information: H,0(g) → H,0(I) AHxn = -45 kJ 2H,0(g) → 2H,(g) + O2(g) AHyn = +480 kJ %3D rxn А. +570 kJ В. +525 kJ С. +435 kJ D. +390 kJ

Calculate AHxn for the reaction: 2H,0(1) → 2H2(g) + O2(g) Use the following information: H,0(g) → H,0(I) AHxn = -45 kJ 2H,0(g) → 2H,(g) + O2(g) AHyn = +480 kJ %3D rxn А. +570 kJ В. +525 kJ С. +435 kJ D. +390 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Calculate Hrxnfor the reaction:2H2O(l) 2H2(g) + O2(g)

Use the following information:H2O(g) H2O(l) Hrxn= -45 kJ

2H2O(g) 2H2(g) + O2(g)Hrxn= +480 kJ

A.+570 kJ

B.+525 kJ

C.+435 kJ

D.+390 kJ

Calculate AHxn for the reaction:
2H,0(1) → 2H2(g) + O2(g)
Use the following information:
H,0(g) → H,0(I)
AHxn = -45 kJ
2H,0(g) → 2H,(g) + O2(g)
AHyn = +480 kJ
%3D
rxn
А.
+570 kJ
В.
+525 kJ
С.
+435 kJ
D.
+390 kJ

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