Calculate AH; (kJ/mol) , enthalpy of formation, for the hypothetical CaF(s) given: AHlattice = -895 kJ/mol AHsub(Ca) = +178 kJ/mol AHje1 (Ca) = +590 kJ/mol AHje2 (Ca) = +1250 kJ/mol AHd(F2) = +158 kJ/mol %3D AHea(F) = -328 kJ/mol 1053 -974 974 874 -1053

Calculate AH; (kJ/mol) , enthalpy of formation, for the hypothetical CaF(s) given: AHlattice = -895 kJ/mol AHsub(Ca) = +178 kJ/mol AHje1 (Ca) = +590 kJ/mol AHje2 (Ca) = +1250 kJ/mol AHd(F2) = +158 kJ/mol %3D AHea(F) = -328 kJ/mol 1053 -974 974 874 -1053

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter4: Energy And Chemical Reactions

Section: Chapter Questions

Problem 75QRT

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