Calculate AH for the reactionCIF9) + F2(9) → CIF3(9)+F2(g)given the following chemical equations and their respective enthalpy changes:1.2CIFg) + Ozig) C20(g) + F2O(g)2.2CIF3(g) *3. 2F20(g)AH=167.5 kJAH=341.4 kJ202(g)C20(g) + 3F20(g)-2F2(g) * O2(g)AH=43.4 kJ4AH=341.4 kJ

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Calculate AH for the reaction CIF(9) + F20)CIF3(9) given the following chemical equations and their respective enthalpy changes: + Ozig) -Cl2Og) + F2O(g) +202g)-Cl20(g) + 3F2O(g) + O2(g) 1. 2CIF AH=167.5 kJ +] (), 2.2CIF3(g) AH=341.4 kJ 3. 2F20(g) 2F2(g) * O2g) AH=43.4 kJ AH-341 4k.

Calculate AH for the reaction CIF(9) + F20)CIF3(9) given the following chemical equations and their respective enthalpy changes: + Ozig) -Cl2Og) + F2O(g) +202g)-Cl20(g) + 3F2O(g) + O2(g) 1. 2CIF AH=167.5 kJ +] (), 2.2CIF3(g) AH=341.4 kJ 3. 2F20(g) 2F2(g) * O2g) AH=43.4 kJ AH-341 4k.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Question

Calculate AH for the reaction
CIF9) + F2(9) → CIF3(9)
+F2(g)
given the following chemical equations and their respective enthalpy changes:
1.2CIFg) + Ozig) C20(g) + F2O(g)
2.2CIF3(g) *
3. 2F20(g)
AH=167.5 kJ
AH=341.4 kJ
202(g)C20(g) + 3F20(g)
-2F2(g) * O2(g)
AH=43.4 kJ
4
AH=341.4 kJ

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