**Exercise 6.128**Use the information provided to calculate the enthalpy change involved in the complete reaction of 3.0 g of carbon to form PbCO₃(s) in reaction 4. Ensure that you provide the correct sign (positive or negative) with your answer.**Reactions and Enthalpy Changes:**1. \( \text{Pb(s)} + \frac{1}{2} \text{O}_2(\text{g}) \rightarrow \text{PbO(s)} \) - \( \Delta H^\circ_{\text{rxn}} = -219 \, \text{kJ} \)2. \( \text{C(s)} + \text{O}_2(\text{g}) \rightarrow \text{CO}_2(\text{g}) \) - \( \Delta H^\circ_{\text{rxn}} = -394 \, \text{kJ} \)3. \( \text{PbCO}_3(\text{s)} \rightarrow \text{PbO(s)} + \text{CO}_2(\text{g}) \) - \( \Delta H^\circ_{\text{rxn}} = 86 \, \text{kJ} \)4. \( \text{Pb(s)} + \text{C(s)} + \frac{3}{2} \text{O}_2(\text{g}) \rightarrow \text{PbCO}_3(\text{s)} \) - \( \Delta H^\circ_{\text{rxn}} = ? \)

Given: Mass of carbon = 3.0 g The equations are as follows, Pb(s) + 12O2(g) → PbO(s)…

6.128. Use the following information to calculate the enthalpy change involved in the complete reaction of 3.0 g of carbon to form PbCO3(s) in reaction 4. Be sure to give the proper sign (positive or negative) with your answer. (1) Pb(s) + }O,g) → PbO(s) -219 kJ rxn (2) C(s)+ O2(g)→CO2(g) AHxn = -394 k] (3) РЬСО,() —> РЬО() + СО,(g) AH 86 k) rxn (4) Pb(s) + C(s) +0,g) → PbCO,(;) ΔΗ %3D rxn

6.128. Use the following information to calculate the enthalpy change involved in the complete reaction of 3.0 g of carbon to form PbCO3(s) in reaction 4. Be sure to give the proper sign (positive or negative) with your answer. (1) Pb(s) + }O,g) → PbO(s) -219 kJ rxn (2) C(s)+ O2(g)→CO2(g) AHxn = -394 k] (3) РЬСО,() —> РЬО() + СО,(g) AH 86 k) rxn (4) Pb(s) + C(s) +0,g) → PbCO,(;) ΔΗ %3D rxn

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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