Calculate AH for 4N204(g) → 2N20(g) + 4NO2 (g) + 302 based on the reactions: 2NO2 (9) + 2NO(@) + O2 (9)→2N2O4 (9) AH1 = -228.54 kJ %3D 4NO(9) + 2N2O(g) + 502 (9)→4N204 (9) A H2 = -488.46 kJ 2NO9) + O2 (9)→ N2O4 (9) AH3 = -171.34 kJ

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Using Hess's Law, calculate for the change in enthalpy of the given reaction.

Calculate ∆ ? for 4N2O4(?) → 2N2O(?) + 4??2 (?) + 3?2 based on the reactions:


2NO2 (g) + 2NO(g) + O2 (g) 2N2O4 (g) ∆H1 = −228.54 kJ
4NO(g) + 2N2O(g) + 5O2 (g) 4N2O4 (g) ∆H2 = −488.46 kJ
 2NO(g) + O2 (g) N2O4 (g) ∆H3 = −171.34 kJ

Calculate AH for 4N204(g)
reactions:
2N20(g) + 4NO2 (g) + 302 based on the
2NO2 (9) + 2NO9) + Oz
2N2O4 (9)
AH1 = -228.54 kJ
4NO(9) + 2N2O(g) + 502 (9)→4N2O4 (9)
A H2 = -488.46 kJ
2NO(9) + O2 (2)N2O4 (g)
AH3 = -171.34 kJ
Transcribed Image Text:Calculate AH for 4N204(g) reactions: 2N20(g) + 4NO2 (g) + 302 based on the 2NO2 (9) + 2NO9) + Oz 2N2O4 (9) AH1 = -228.54 kJ 4NO(9) + 2N2O(g) + 502 (9)→4N2O4 (9) A H2 = -488.46 kJ 2NO(9) + O2 (2)N2O4 (g) AH3 = -171.34 kJ
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