Calculate AG°, in kJ, for the reaction: CIO, (aq) + 6 H*(aq) +3 Pb(s) → CI(aq) + 3 Pb2*(aq) + 3 H2O(I) Given that E cell =1.58 V AG°=_ kJ Report your answer to three significant figures. Do not include units in your answer.

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Calculate AG°, in kJ, for the reaction:
CIO3 (aq) + 6 H*(aq) +3 Pb(s) CIF(aq) + 3 Pb2(aq) + 3 H2O(1)
Given that E cell =1.58 V
AG =
kJ
Report your answer to three significant figures. Do not include units in your answer.
Transcribed Image Text:Calculate AG°, in kJ, for the reaction: CIO3 (aq) + 6 H*(aq) +3 Pb(s) CIF(aq) + 3 Pb2(aq) + 3 H2O(1) Given that E cell =1.58 V AG = kJ Report your answer to three significant figures. Do not include units in your answer.
Expert Solution
Step 1: Standard Gibbs Free Energy

The change in standard Gibbs free energy (Go) for a cell reaction is expressed as:

Go=-nFEcello         ......................... (1)

Where:

n is the total number of electrons exchanged.

1 F = 96500 C

Ecello is the standard cell potential.

Step 2: Number of Electron Exchanged

3×[Oxidation: Pb(s)Pb2+(aq)+2e-]

Reduction: ClO3-(aq)+6H+(aq)+6e-Cl-(aq)+3H2O(l)

-------------------------------------------------------------------------

Overall: ClO3-(aq)+3Pb(s)+6H+(aq)Cl-(aq)+3Pb2+(aq)+3H2O(l)

Hence, a total of six electrons are exchanged during the overall reaction.

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