CHALLENGEACTIVITYCritical values for quick reference during this activity.Confidence level Critical valuez* = 1.645z* = 1.9600.900.950.994.8.1: Confidence intervals for population proportions.476172.1877292 qx3zqy7COz* = 2.576PROPERTY OF QUILEOIDEJump to level 1A poll for a statewide election has a margin of error of 2.83 percentage points.How many voters should be sampled for a 99% confidence interval? Round upto the nearest whole number.Ex: 1234 voters4CheckNextEzyBooks catalogFeedback?

We have given that, Confidence interval = 99% or 0.99 and margin of error (E) = 2.83% = 0.0283

Answered: cal values for quick reference during…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Confidence Interval for One Population Mean In 1903, a paper published by Abigail Camp Dimon, discussed the effect of environment on the shape and form of two sea snail species. Nassa obsoleta and Nassa trivittata. One of the variables that Dimon considered was the length of the shell. A random sample of 256 N. trivittata specimens was selected. The average shell length for the sample was 12 mm., with a standard deviation of 4 mm. Find the 95% confidence interval for the average shell length of all N. trivittata sea snails. What is the margin of error used to calculate this interval? Do not round.
CHALLENGE 7.2.1: Confidence intervals for population proportions. ACTIVITY Critical values for quick reference during this activity. Confidence level Critical value 0.90 z* = 1.645 0.95 z* = 1.960 0.99 2 = 2.576 3876741891676.qv3ny Start In a poll of 1000 randomly selected voters in a local election, 393 voters were against school bond measures. What is the sample proportionp? Ex 0.123 What is the margin of error m for the 90% confidence level? Ex: 0.123 Check 73°F A search F7 F9 F10 FIL F12 5 8. T Y H K D D D D
Construct a 90% confidence interval to estimate the population mean using the data below. What assumptions need to be made about this population? x=38 s=9.9 n=24 Click here to view page 1 of the critical t-score table. Click here to view page 2 of the critical t-score table. Question content area bottom Part 1 The 90%confidence interval for the population mean is from a lower limit of here to an upper limit of (Round to two decimal places as needed.) Part 2 What assumptions need to be made about this population? A. The population distribution is skewed to one side. B. The population size is larger than 30. C. The population follows the Student's t-distribution. D. The population follows the normal probability distribution.
Question 34 What is the GENERAL FORM for a confidence interval for either the population mean or the population proportion? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a P.E. = Population Parameter + (Multiplier)*S.E.(P.E.) Population Parameter P.E. ± (Multiplier)*S.E.(P.E.) Population Parameter = P.E. ± (Multiplier)*P.E. d Population Parameter < P.E. < Population Parameter
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
question#5 Assume that a sample is used to estimate a population mean μμ. Find the 99.5% confidence interval for a sample of size 73 with a mean of 26.5 and a standard deviation of 14.4. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places.99.5% C.I. =
If n=27, ¯x(x-bar)=36, and s=20, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place._____ < μ < _____
If n=15n=15, ¯xx¯=43, and s=20s=20, construct a confidence interval at a 90% confidence level. Give your answers to one decimal place. _____< μ < _____ Technology
Question 5 You are interested in finding a 95% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 15 randomly selected college students. Round answers to 3 decimal places where possible. 7 ▼ < 2 12 11 6 10 7 5 3 10 Submit Question 5 0 7 2 5 a. To compute the confidence interval use a ? distribution. b. With 95% confidence the population mean number of days of class that college students miss is between and days. c. If many groups of 15 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of missed class days and about percent will not contain the true population mean number of missed class days.
Question3: It is known that the population wellbeing level follows a normal distribution. The wellbeing levels of 9 male is shown below. 2 | 247 3 | 34569 4 | 7 Use the sample data to calculate the 95% confidence interval Would we reject the hypothesis that the male has a statistically significant different wellbeing level from female at a 1% significance level? (hint: use the data above to conduct a statistic test, specify 4 steps)
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
If n= 21, x¯(x-bar)= 37, and s= 20, construct a confidence interval at a 99% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place. ____ < μ < ___

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