Question 2▼ < >You are interested in finding a 95% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute milesfor 11 randomly selected non-residential college students. Round answers to 3 decimal placeswhere possible.8 8 28 7 22 1324 8 24 8 24a. To compute the confidence interval use a✓distribution.b. With 95% confidence the population mean commute for non-residential college students isbetweenandmiles.c. If many groups of 11 randomly selected non-residential college students are surveyed, then adifferent confidence interval would be produced from each group. Aboutpercent ofthese confidence intervals will contain the true population mean number of commute miles andaboutpercent will not contain the true population mean number of commute miles.Hint: HintsVideo [+]fg12f10fnSubmit Question♫+90144DIIDDI

Given data is: 8 8 28 7 22 13 24 8 24 8 24 Total number of students =11 a) as sample size is…

Answered: You are interested in finding a 95%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 11 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 18 6 28 15 15 16 9 8 28 15 17 a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 11 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per patient.
Pls help me answer number 2
You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 18 12 10 9 15 5 9 6 18 5 17 11 6 a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 13 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per patient.
You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 12 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 25 14 23 8 6 15 18 5 8 17 9 7 a. To compute the confidence interval use a ? z t Correct distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between blank and blank visits. c. If many groups of 12 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About # percent of these confidence intervals will contain the true population mean number of visits per patient and about # percent will not contain the true population mean number of visits per patient.
You are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 15 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 8 15 5 18 9 28 5 14 23 25 18 20 23 9 16 a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 15 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About ____percent of these confidence intervals will contain the true population mean number of visits per patient and about ____percent will not contain the true population mean number of visits per patient.
You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 11 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 27 5 28 22 15 9 16 10 25 18 5 a. To compute the confidence interval use a Z OR T distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between ? and ? visits. c. If many groups of 11 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About ? percent of these confidence intervals will contain the true population mean number of visits per patient and about ? percent will not contain the true population mean number of visits per patient.
You are interested in finding a 98% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 11 randomly selected non-residential college students. Round answers to 3 decimal places where possible. 18 18 27 17 15 7 11 15 9 12 19 a. With 98% confidence the population mean commute for non-residential college students is between _____ and____miles. b. If many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About (____) percent of these confidence intervals will contain the true population mean number of commute miles and about(_____) percent will not contain the true population mean number of commute miles.
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
Pls help me answer number 3
Section b
The frequency distribution below shows the amount of time the 50 randomly selected students spend playing video games daily. Complete the table below. Show your solutions and answer the given questions. Number of Frequency minutes (f) Lower boundaries (LB) Less than cumulative frequency (< cf) 151-180 4 121-150 9 91-120 16 61-90 10 31-60 9 1-30 2 i = 30 N=50 1. How many students belong to the upper quartile? 2. Find the 5th decile. Interpret the result. 3. Solve for P80. Interpret the result.
You are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 15 26 28 28 14 11 18 20 5 19 15 14 19 a. To compute the confidence interval use a Correct distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 13 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per

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