CaC204 + H,SO4 K,So4 + MnSO4 + Caso4 + CO2 + H20 2. KMN04 + Substance oxidized: Substance reduced: Balanced equation:

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please follow the steps in the other picture

Cr203 + NazCO3 + KNO3 ----> Na2CrO4 + CO2 + KNO2
Step 1:
3+ 2-
1+ 4- 2-
1+ 5+ 2-
1+ 6+ 2-
1+ 3+ 2-
4+ 2-
Cr2 O3 + Naz C 03 + KN O3 ---> Na2 Cr 04 + K N O2 +C O2
Step 2:
The oxidation number of Cr changes from 3+ to 6+. Likewise, that of N changes from 5+ to 3+.
Step 3:
3+
Cr2O3 + NazCO3 + KNO3 ---> NazCrO4 + CO2 + KNO2
3 e lost
5+
6+
3+
2.e gained
Step 4:
Cr2O3 + NazCOa+ KNO3 ---> 2 Na2CrO4_ + CO2 + KNO2
|3 e lost x 26 e
Ze gained 1 = 2 e
Step 5:
Cr2O3 + NazC03 + KNO3 ----> 2 Na2CrO4 ,+ CO2 +
6 e x 1 = 6 e
KNO2
Zex3-6e
The appropriate factors are 1 and 3.
1 Cr203 + NazCO3 + 3 KNO3
----> (1 x 2) Na2CrO4 + CO2 + 3 KNO2
Transcribed Image Text:Cr203 + NazCO3 + KNO3 ----> Na2CrO4 + CO2 + KNO2 Step 1: 3+ 2- 1+ 4- 2- 1+ 5+ 2- 1+ 6+ 2- 1+ 3+ 2- 4+ 2- Cr2 O3 + Naz C 03 + KN O3 ---> Na2 Cr 04 + K N O2 +C O2 Step 2: The oxidation number of Cr changes from 3+ to 6+. Likewise, that of N changes from 5+ to 3+. Step 3: 3+ Cr2O3 + NazCO3 + KNO3 ---> NazCrO4 + CO2 + KNO2 3 e lost 5+ 6+ 3+ 2.e gained Step 4: Cr2O3 + NazCOa+ KNO3 ---> 2 Na2CrO4_ + CO2 + KNO2 |3 e lost x 26 e Ze gained 1 = 2 e Step 5: Cr2O3 + NazC03 + KNO3 ----> 2 Na2CrO4 ,+ CO2 + 6 e x 1 = 6 e KNO2 Zex3-6e The appropriate factors are 1 and 3. 1 Cr203 + NazCO3 + 3 KNO3 ----> (1 x 2) Na2CrO4 + CO2 + 3 KNO2
KMN04 +
H2SO4→ K,SO4 + MnSO4 + CasO4 + CO2 + H20
2.
CaC204 +
Substance oxidized:
Substance reduced:
Balanced equation:
Transcribed Image Text:KMN04 + H2SO4→ K,SO4 + MnSO4 + CasO4 + CO2 + H20 2. CaC204 + Substance oxidized: Substance reduced: Balanced equation:
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