CaC2. Given the thermochemical equations below, calculate the ΔHfo for acetylene in kJ/rxn. CaO(s) + H2O(l) ---> Ca(OH)2(s) ΔH = - 65.3 kJ/rxn CaO(s) + 3C(s, graphite) ---> CO(g)+ CaC2(s) ΔH = + 462.3 kJ/rxn CaC2(s) + 2 H2O(l) ---> Ca(OH)2(s) + C2H2(g) ΔH = - 126.0 kJ/rxn 2C(s, graphite) + O2(g) ---> 2CO(g) ΔH = - 221.0 kJ/rxn 2 H2O(l) ---> 2H2(g) + O2(g) ΔH = + 572.0 kJ/rxn
CaC2. Given the thermochemical equations below, calculate the ΔHfo for acetylene in kJ/rxn. CaO(s) + H2O(l) ---> Ca(OH)2(s) ΔH = - 65.3 kJ/rxn CaO(s) + 3C(s, graphite) ---> CO(g)+ CaC2(s) ΔH = + 462.3 kJ/rxn CaC2(s) + 2 H2O(l) ---> Ca(OH)2(s) + C2H2(g) ΔH = - 126.0 kJ/rxn 2C(s, graphite) + O2(g) ---> 2CO(g) ΔH = - 221.0 kJ/rxn 2 H2O(l) ---> 2H2(g) + O2(g) ΔH = + 572.0 kJ/rxn
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.42QE: The combustion of 1.00 mol liquid methyl alcohol (CH3OH) in excess oxygen is exothermic, giving 727...
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Acetylene, C2H2, a gas used in welding torches, is produced by the action of water on calcium carbide, CaC2. Given the thermochemical equations below, calculate the ΔHfo for acetylene in kJ/rxn.
CaO(s) + H2O(l) ---> Ca(OH)2(s) ΔH = - 65.3 kJ/rxn
CaO(s) + 3C(s, graphite) ---> CO(g)+ CaC2(s) ΔH = + 462.3 kJ/rxn
CaC2(s) + 2 H2O(l) ---> Ca(OH)2(s) + C2H2(g) ΔH = - 126.0 kJ/rxn
2C(s, graphite) + O2(g) ---> 2CO(g) ΔH = - 221.0 kJ/rxn
2 H2O(l) ---> 2H2(g) + O2(g) ΔH = + 572.0 kJ/rxn
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