C6. You have been doing researc drinking among teens. is as the number of times the teen drank five or more alcoholic drinks during th ied Construct the 95% confidence interval for the true average severe binge drinking scora b. Your roommate is concerned about your confidence interval calculation, arguined severe binge drinking scores are not normally distributed, which in turn makes the confidence interval calculation meaningless. Assume your roommate is correct about the distribution of severe binge drinking scores. Does that imply that the calculation of a confidence interval is not appropriate? Why or why not?
C6. You have been doing researc drinking among teens. is as the number of times the teen drank five or more alcoholic drinks during th ied Construct the 95% confidence interval for the true average severe binge drinking scora b. Your roommate is concerned about your confidence interval calculation, arguined severe binge drinking scores are not normally distributed, which in turn makes the confidence interval calculation meaningless. Assume your roommate is correct about the distribution of severe binge drinking scores. Does that imply that the calculation of a confidence interval is not appropriate? Why or why not?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:your
election today. What is
C6. You have been doing research for your statistics class on the prevalence of bines
drinking among teens.
a. According to 2011 Monitoring the Future data, the average binge drinking score c..
sample of 914 teens, is 1.27, with a standard deviation of 0.80. Binge drinking ie dac th
as the number of times the teen drank five or more alcoholic drinks during the pocu
Construct the 95% confidence interval for the true average severe binge drinking co
Score.
b. Your roommate is concerned about your confidence interval calculation, arguing sh
severe binge drinking scores are not normally distributed, which in turn makes the
confidence interval calculation meaningless. Assume your roommate is correct about
the distribution of severe binge drinking scores. Does that imply that the calculation
of a confidence interval is not appropriate? Why or why not?
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