C2H6 breaks down into 2 radicals CH3 at 700C, K=1.98H^-1 a) what is the order of the reaction, provide a detailed explanation. b) what is the half life of C2H6 (in hours) c) given a 500mL container, at 700C, calculate the time (in hours) required for the amount of C2H6 to go down from 1.15*10^-3 mole to 2.35*10^-4 mole

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