C1 and C2 are arbitrary constants. Note: Y1(t) 2t and y2(t) = e2t are independent solutions of y" – 4y = 0. e The complementary function of y" – 4y = 4et is y3(t) = C1e-2t + C2e²t. Y4(t) = et is a particular solution of y" – 4y = 4et. - The general solution of y" – 4y = 4et is y5(t) = C1e¯2t + C2e²t + est. 8 5t 21

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