C. Which of the following graphs could represent, to the same scale, the force exerted by the scale on each ball a9 function of time? Select an answer for the rubber ball and an answer for the clay ball. F (N) F (N) E (N)

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Part c.
explain why graph e goes with the rubber ball? 
Explain why graph D goes with the clay ball? 

**Physics Experiment: Momentum and Impulse**

A rubber ball and a clay ball have equal mass and are dropped onto a digital scale from the same height. The rubber ball bounces back to nearly the same height, while the clay ball sticks to the scale upon impact.

**Exercise Questions:**

**a. Momentum Ratio Analysis**
- *Question*: What is the ratio of the change of the rubber ball’s momentum to the change of the clay ball’s momentum?
- *Solution*: The momentum change of the clay ball is 0 (since it does not rebound). Thus, for the rubber ball \((mv + mv\)) and clay ball \((mv - 0)\), the ratio \(\frac{\Delta p_{\text{rubber}}}{\Delta p_{\text{clay}}}\) is 2.

**b. Impulse Ratio Analysis**
- *Question*: What is the ratio of the impulse imparted to the rubber ball to the impulse imparted to the clay ball?
- *Solution*: Impulse is the same as the change in momentum. Therefore, the ratio of impulse for rubber to clay is also 2.

**c. Force-Time Graph Interpretation**
- *Question*: Which of the following graphs represent, to the same scale, the force exerted by the scale on each ball as a function of time? For the rubber ball, the correct graph shows a quick, sharp impulse, while for the clay ball, a more gradual increase with no rebound.
  
  **Graph Analysis:**
  - **Rubber Ball**: Graph E represents a sharp peak, indicating the quick force and rebound of the rubber ball.
  - **Clay Ball**: Graph D shows a rise and stop, indicating the force applied until the ball stops without bouncing.

This exercise demonstrates the concepts of momentum, impulse, and how different materials respond to forces upon impact.
Transcribed Image Text:**Physics Experiment: Momentum and Impulse** A rubber ball and a clay ball have equal mass and are dropped onto a digital scale from the same height. The rubber ball bounces back to nearly the same height, while the clay ball sticks to the scale upon impact. **Exercise Questions:** **a. Momentum Ratio Analysis** - *Question*: What is the ratio of the change of the rubber ball’s momentum to the change of the clay ball’s momentum? - *Solution*: The momentum change of the clay ball is 0 (since it does not rebound). Thus, for the rubber ball \((mv + mv\)) and clay ball \((mv - 0)\), the ratio \(\frac{\Delta p_{\text{rubber}}}{\Delta p_{\text{clay}}}\) is 2. **b. Impulse Ratio Analysis** - *Question*: What is the ratio of the impulse imparted to the rubber ball to the impulse imparted to the clay ball? - *Solution*: Impulse is the same as the change in momentum. Therefore, the ratio of impulse for rubber to clay is also 2. **c. Force-Time Graph Interpretation** - *Question*: Which of the following graphs represent, to the same scale, the force exerted by the scale on each ball as a function of time? For the rubber ball, the correct graph shows a quick, sharp impulse, while for the clay ball, a more gradual increase with no rebound. **Graph Analysis:** - **Rubber Ball**: Graph E represents a sharp peak, indicating the quick force and rebound of the rubber ball. - **Clay Ball**: Graph D shows a rise and stop, indicating the force applied until the ball stops without bouncing. This exercise demonstrates the concepts of momentum, impulse, and how different materials respond to forces upon impact.
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