C. What is the reduction potential of the reaction shown below at 298 K by using Nernst Equation : E°= E°. Q= (conc'n of ox)ese exp cell-0.0591 log Q ( conc'n of red)- exp 1. 1. Al(s) + Fe-aq) → Al*(aq) + Fe(s) [Fe*]=0.40M [Al*]=0.55M Fe2 + 2e= -0.44V Al*3 + 3e= -1.66V 2. Mg(s) + Ag"aq) → Mg*(aq) + Ag(s) [Mg]=0.35M [Ag+]=0.67M Mg2 + 2e= -2.37V Ag1 + 1e= 0.80V

C. What is the reduction potential of the reaction shown below at 298 K by using Nernst Equation : E°= E°. Q= (conc'n of ox)ese exp cell-0.0591 log Q ( conc'n of red)- exp 1. 1. Al(s) + Fe-aq) → Al(aq) + Fe(s) [Fe]=0.40M [Al]=0.55M Fe2 + 2e= -0.44V Al3 + 3e= -1.66V 2. Mg(s) + Ag"aq) → Mg*(aq) + Ag(s) [Mg]=0.35M [Ag+]=0.67M Mg2 + 2e= -2.37V Ag1 + 1e= 0.80V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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