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C. Standardization Weight of vial and KHPH 59.0g Weight after 1st transfer 59-2 Weight after 2nd transfer 56-5 Weight after 3rd transfer 55.6 Weight of KHPH in flask I (show calculations) 0-89 So-9-S82 Weight of KHPh in flask II (show calculations) 1-79 5a-2-56-5 Weight of KHPh in flask III (show calculations) 0.99 56-5-55-6 I II II O.00 ml 27-00 S1-00 Initial volume reading of NaOH as.coml SI-00 30-00 Final volume reading of NaOH 25-00 ml 24.00ml 29.00ml Volume of NaOH used Molarity of NaOH Show calculations for all Trials Below:

C. Standardization Weight of vial and KHPH 59.0g Weight after 1st transfer 59-2 Weight after 2nd transfer 56-5 Weight after 3rd transfer 55.6 Weight of KHPH in flask I (show calculations) 0-89 So-9-S82 Weight of KHPh in flask II (show calculations) 1-79 5a-2-56-5 Weight of KHPh in flask III (show calculations) 0.99 56-5-55-6 I II II O.00 ml 27-00 S1-00 Initial volume reading of NaOH as.coml SI-00 30-00 Final volume reading of NaOH 25-00 ml 24.00ml 29.00ml Volume of NaOH used Molarity of NaOH Show calculations for all Trials Below:

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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volume of the added sodium hydroxide is noted, and the concentration of the NaOH is calculated. SAMPLE OF CALCULATIONS 50 ml of NaOH solution is used to titrate 1.0 g of KHph to the end point. Calculate the molarity of NaOH solution? KHPh used =1.00 g Volume of NaOH used = 0.0500 L 1 mole 1 mole NaOH Moles of NaOH = 1.00g KHPh x = 4.90x 10¯ 3 204 g 4.90x 10³ moles 1 mole KHPH -3 MolarityNaOH =0.0980M 5.00x 10 1
Transcribed Image Text:volume of the added sodium hydroxide is noted, and the concentration of the NaOH is calculated. SAMPLE OF CALCULATIONS 50 ml of NaOH solution is used to titrate 1.0 g of KHph to the end point. Calculate the molarity of NaOH solution? KHPh used =1.00 g Volume of NaOH used = 0.0500 L 1 mole 1 mole NaOH Moles of NaOH = 1.00g KHPh x = 4.90x 10¯ 3 204 g 4.90x 10³ moles 1 mole KHPH -3 MolarityNaOH =0.0980M 5.00x 10 1
C. Standardization Weight of vial and KHPH 59.0g Weight after 1st transfer 59-2 Weight after 2nd transfer 56-5 Weight after 3rd transfer 55.6 Weight of KHPh in flask I (show calculations) 0-89 50-9-582 Weight of KHPh in flask II (show calculations) 1-79 5a-2-56-5 Weight of KHPh in flask III (show calculations) 0-99 56-5-55-6 I II II O-00 ml 27-00 SI-00 Initial volume reading of NaOH as.00ml SI-00 80-00 Final volume reading of NaOH 24.00 ml 29.00ml 25.00 ml Volume of NaOH used Molarity of NaOH Show calculations for all Trials Below:
Transcribed Image Text:C. Standardization Weight of vial and KHPH 59.0g Weight after 1st transfer 59-2 Weight after 2nd transfer 56-5 Weight after 3rd transfer 55.6 Weight of KHPh in flask I (show calculations) 0-89 50-9-582 Weight of KHPh in flask II (show calculations) 1-79 5a-2-56-5 Weight of KHPh in flask III (show calculations) 0-99 56-5-55-6 I II II O-00 ml 27-00 SI-00 Initial volume reading of NaOH as.00ml SI-00 80-00 Final volume reading of NaOH 24.00 ml 29.00ml 25.00 ml Volume of NaOH used Molarity of NaOH Show calculations for all Trials Below:
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