© Macmillan Learning A nucleus of the boron-11 isotope consists of five protons and six neutrons. A particular ionized atom of boron-11, whose mass is 1.83 x 10-26 kg, lacks 3 electrons from its neutral state. Find the magnitude and direction of the electric field that will levitat this ion, exactly balancing its weight. Take g = 9.81 m/s². magnitude: direction: downward cannot be determined upward horizontal N/C

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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O Macmillan Learning
A nucleus of the boron-11 isotope consists of five protons and six neutrons. A particular ionized atom of boron-11, whose mass
is 1.83 × 10−26 kg, lacks 3 electrons from its neutral state. Find the magnitude and direction of the electric field that will levitate
9.81 m/s².
this ion, exactly balancing its weight. Take g
=
magnitude:
direction:
downward
cannot be determined
O upward
horizontal
N/C
Transcribed Image Text:O Macmillan Learning A nucleus of the boron-11 isotope consists of five protons and six neutrons. A particular ionized atom of boron-11, whose mass is 1.83 × 10−26 kg, lacks 3 electrons from its neutral state. Find the magnitude and direction of the electric field that will levitate 9.81 m/s². this ion, exactly balancing its weight. Take g = magnitude: direction: downward cannot be determined O upward horizontal N/C
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