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C++ Function to remove the first node of a linked list
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- C++ Consider the following function as a property of a LinkedBag that contains a Doubly Linked List. Assume a Node has pointers prev and next, which can be read and changed with the standard get and set methods. Assume that the doubly linked list is: 1 <--> 2 <--> 3 <--> 4 <--> 5 <-->6 If you are uncertain what the above diagram depicts, it is a doubly linked list such that: The head of this doubly linked list is the node that contains the value 1. The tail of this doubly linked list is the node that contains the value 6. The 3rd node in this list contains the value 3. The contents of this list are the values 1 through 6 in sequential order. The following questions are regarding the linked list after after the test_function is run. A. The head of the list after the test_function is run contains the value: B. The tail of the list after the test_function is run contains the value: C. The 3rd node in the list after the test_function is run…C++ DOUBLY LINKED LIST: Implement the remove_between function for my code: Incomplete code: #include <cstdlib>#include <iostream>using namespace std; class DoublyLinkedList : public List { node* head; node* tail; int index; node* create_node(int num, node* predecessor, node* successor) { node* n = (node*) malloc( sizeof(node) ); n->element = num; n->next = successor; n->prev = predecessor; return n; } void add_between(int num, node* predecessor, node* successor) { node* newest = create_node(num, predecessor, successor); predecessor->next = newest; successor->prev = newest; index++; } void remove_between(int num, node* predecessor, node* successor) { ///// CODE HERE }Please fill in the blanks for C. // Singly Linked List #include<stdio.h> // Part 1 //Declare a node of character // each node has a value and a pointer that points to the next node struct charNode { __1__ val; __2__ __3__ next; }; /*This function takes the first pointer (head) and iterates through the list to print one character at a time.*/ __4__ printCharLL(__5__ __6__ curPtr) { printf("\nPrinting back the list: \n"); while(__7__ __8__ __9__) //condition to keep running the loop { printf("%c", __10__); //print the value using pointer, no spaces curPtr = __11__; //move the pointer to point to the next node in list, no spaces } printf("\n"); } // Part 2 //Declare a node of double // each node has a value and a pointer that points to the next node struct doubleNode { __12__ val; __13__ __14__ next; };…
- Suppose a node of a doubly linked list is defined as follows: struct Node{ int data; struct Node* next; struct Node* prev; }; Write the function definition of the function deleteElement as presented below. This function deletes a node at position n from a doubly linked list. struct Node* deleteElement(struct Node* head, int n){ //write the function definition }Data Structures and algorithms: Topic: Doubly and circular Linked Lists in java: Please solve this on urgent basis: Attach output's picture and explain every statement in commments: Implemented Circular Linked List CODE: #include <bits/stdc++.h> // include the standard c++ header fileusing namespace std; class Node // definition of the class for the node of the linked list{public: int data; Node* next;}; void push(Node** head_ref, int data) // definition of the function to insert the element in the list{ Node* ptr1 = new Node(); ptr1->data = data; ptr1->next = *head_ref; if (*head_ref != NULL) // when the head of the list does not points to null { Node* temp = *head_ref; while (temp->next != *head_ref) temp = temp->next; temp->next = ptr1; } else…1)Write a Java program which stores three values by using singly linked list.- Node class1. stuID, stuName, stuScore, //data fields2. constructor3. update and accessor methods- Singly linked list class which must has following methods:1. head, tail, size// data fields2. constructor3. update and accessor methodsa. getSize() //Returns the number of elements in the list.b. isEmpty( ) //Returns true if the list is empty, and false otherwise.c. getFirstStuID( ), getStuName( ), getFirstStuScore( )d. addFirst(stuID, stuName, stuScore)e. addLast(stuID, stuName, stuScore)f. removeFirst ( ) //Removes and returns the first element of the list.g. displayList( ) //Displays all elements of the list by traversing the linked list.- Test class – initialize a singly linked list instance. Test all methods of singly linked list class. 2. Write a Java program which stores three values by using doubly linked list.- Node class4. stuID, stuName, stuScore, //data fields5. constructor6. update and…
- C++ Given code #include <iostream>using namespace std; class Node {public:int data;Node *pNext;}; void displayNumberValues( Node *pHead){while( pHead != NULL) {cout << pHead->data << " ";pHead = pHead->pNext;}cout << endl;} //Option 1: Search the list// TODO: complete the function below to search for a given value in linked lsit// return true if value exists in the list, return false otherwise. ?? linkedlistSearch( ???){ } //Option 2: get sum of all values// TODO: complete the function below to return the sum of all elements in the linked list. ??? getSumOfAllNumbers( ???){ } int main(){int userInput;Node *pHead = NULL;Node *pTemp;cout<<"Enter list numbers separated by space, followed by -1: "; cin >> userInput;// Keep looping until end of input flag of -1 is givenwhile( userInput != -1) {// Store this number on the listpTemp = new Node;pTemp->data = userInput;pTemp->pNext = pHead;pHead = pTemp;cin >> userInput;}cout <<"…Write C code that implements a soccer team as a linked list. 1. Each node in the linkedlist should be a member of the team and should contain the following information: What position they play whether they are the captain or not Their pay 2. Write a function that adds a new members to this linkedlist at the end of the list.struct remove_from_front_of_dll { // Function takes no parameters, removes the book at the front of a doubly // linked list, and returns nothing. void operator()(const Book& unused) { //// TO-DO (13) |||| // Write the lines of code to remove the book at the front of "my_dll", // // Remember, attempting to remove an element from an empty data structure is // a logic error. Include code to avoid that. ///// END-TO-DO (13) //// } std::list& my_dll; };
- C++ The List class represents a linked list of dynamically allocated elements. The list has only one member variable head which is a pointer that leads to the first element. See the following code for the destructor to List. ~ List () { for (int i = 0; i <size (); i ++) { pop_back (); } } What problems does the destructor have? Select one or more options: 1. There are no parameters for the destructor. 2. The return value from pop_back (if any) is nerver handled. 3. The destructor will create a stack overflow. 4. The destructor will create dangling pointers. 5.The destructor will create memory leaks. 6.The destructor will create undefined behavior (equivalent to zero pointer exception). 7.The condition must be: i <size () - 1 8. There is at least one problem with the destructor, but none of the above.C++ ProgrammingActivity: Linked List Stack and BracketsExplain the flow of the code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow #include "stack.h" #include "linkedlist.h" // SLLStack means Singly Linked List (SLL) Stack class SLLStack : public Stack { LinkedList* list; public: SLLStack() { list = new LinkedList(); } void push(char e) { list->add(e); return; } char pop() { char elem; elem = list->removeTail(); return elem; } char top() { char elem; elem = list->get(size()); return elem; } int size() { return list->size(); } bool isEmpty() { return list->isEmpty(); } };program Linked List: modify the following program to make a node containing data values of int, char, and string. #include <iostream> using namespace std; struct node { int data; struct Node *next; }; struct Node* head = nullptr;//or Null or 0; void insert(int new_data) { struct Node* new_node=(struct Node*) new(struct Node); new_mode->data=new_data; new_mode->next=head; head=new_node; } void display() { struct Node* ptr; ptr=head; while(ptr ! = NULL) { cout<<ptr->data<<""; ptr=ptr->next; } } int main() { insert{2}; display{}; return0; }