Answer the following questions about the given statement:∃c : Course • c.type = Boxing ∧∃co : Customer • (co,c) ∈Books ∧∃t : Trainer •(t,c) ∈Teaches ∧t.credit >1•What does this statement mean?•Is this statement a set or a predicate?•What does the statement evaluate to based on the current system state? Examples for reference:•∃g : Owner • g.name = gymowner ∧g.email = test-There exists an owner with the name gymowner and email test-predicate-false•{c : Course |∃co : Customer • (co,c) ∈Books}-Set of all Courses which are booked by a customer-set-{Boxing,WeightLifting,Yoga1,Wrestling}•{t : Trainer |#{c : Course |(t,c) ∈Teaches}>1}-Set of all Trainers who teach more than 1 class.-set-{Trainer 2} Teaches association between Owner/Teacher and CourseGym Owner: Ownername = GymOwneremail = gymowner@gym.compassword=gymownerTrainer 1: Trainername Trainer1email trainer1@gym.compassword = trainer1credit - 3Trainer 2: Trainername Trainer2email trainer2@gym.compassword = trainer2credit = 2Wrestling : Coursetime = 2type = Wrestlingid = 1private=falseBoxing: Coursetime = 2type = Boxingid = 2private = falseWeightlifting Coursetime = 2typeid=3private = falseWeightliftingYogal: Coursetime = 3type = Yogaid = 4private = trueYoga2: Coursetime = 4type = Yogaid = 5private = falseCustomer 1: Customername Customer1email= customer1@gym.compasswordcustomer1classcreditclass credit - 0Customer 2: Customername Customer2email customer2@gym.compassword = customer2classcreditclass credit = 1Customer 3: Customername Customer3email customer3@gym.compassword customerclasscreditclass credit = 4Customer 4: Customername Customer4email = customer4@gym.compassword = customer4classcreditclass credit = 5Customer 5: Customername Customer5email customer5@gym.compassword customer5classcreditclass credit 1Customer 6: Customername Customer6email customer6@gym.comcustomer6passwordclasscreditclass credit = 10Customer 7: Customername Customer7email customer7@gym.comcustomer7passwordclasscreditclass credit = 2Books association between Course and Customer

^ - and ∈ - belongs to ∃ - there exists An example of such is •∃c : Course • c.type = boxing ∧ Some…

Answered: ∃c : Course • c.type = Boxing ∧∃co :…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Answer the following questions about the given statement:

∃c : Course • c.type = Boxing ∧∃co : Customer • (co,c) ∈Books ∧∃t : Trainer •
(t,c) ∈Teaches ∧t.credit >1

•What does this statement mean?
•Is this statement a set or a predicate?
•What does the statement evaluate to based on the current system state?

Examples for reference:
•∃g : Owner • g.name = gymowner ∧g.email = test
-There exists an owner with the name gymowner and email test
-predicate
-false

•{c : Course |∃co : Customer • (co,c) ∈Books}
-Set of all Courses which are booked by a customer
-set
-{Boxing,WeightLifting,Yoga1,Wrestling}

•{t : Trainer |#{c : Course |(t,c) ∈Teaches}>1}
-Set of all Trainers who teach more than 1 class.
-set
-{Trainer 2}

Teaches association between Owner/Teacher and Course
Gym Owner: Owner
name = GymOwner
email = gymowner@gym.com
password=gymowner
Trainer 1: Trainer
name Trainer1
email trainer1@gym.com
password = trainer1
credit - 3
Trainer 2: Trainer
name Trainer2
email trainer2@gym.com
password = trainer2
credit = 2
Wrestling : Course
time = 2
type = Wrestling
id = 1
private=false
Boxing: Course
time = 2
type = Boxing
id = 2
private = false
Weightlifting Course
time = 2
type
id=3
private = false
Weightlifting
Yogal: Course
time = 3
type = Yoga
id = 4
private = true
Yoga2: Course
time = 4
type = Yoga
id = 5
private = false
Customer 1: Customer
name Customer1
email= customer1@gym.com
password
customer1
classcredit
class credit - 0
Customer 2: Customer
name Customer2
email customer2@gym.com
password = customer2
classcredit
class credit = 1
Customer 3: Customer
name Customer3
email customer3@gym.com
password customer
classcredit
class credit = 4
Customer 4: Customer
name Customer4
email = customer4@gym.com
password = customer4
classcredit
class credit = 5
Customer 5: Customer
name Customer5
email customer5@gym.com
password customer5
classcredit
class credit 1
Customer 6: Customer
name Customer6
email customer6@gym.com
customer6
password
classcredit
class credit = 10
Customer 7: Customer
name Customer7
email customer7@gym.com
customer7
password
classcredit
class credit = 2
Books association between Course and Customer

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