C; – Co х =1-exp| 2Vdt 0.8 –0.25 5×10 =1– exp %3D 1.2 -0.25 21.6x10-" xt 5×10 0.57894 =1-exp 21.6×1011 xt 5×10 =1–0.57894 exp 2/1.6x10-1" × t 5×10 exp 0.41205 2/1.6×10-" ×. -11 5×10 = 0.41205 exp 8×10°t 62.5 exp = 0.41205 62.5 = 0.3924 62.5 0.3924 62.5 0.3924 159.276= Vt 25368.923 s =t 25368.923 3600 t = 7.0469 hr.
C; – Co х =1-exp| 2Vdt 0.8 –0.25 5×10 =1– exp %3D 1.2 -0.25 21.6x10-" xt 5×10 0.57894 =1-exp 21.6×1011 xt 5×10 =1–0.57894 exp 2/1.6x10-1" × t 5×10 exp 0.41205 2/1.6×10-" ×. -11 5×10 = 0.41205 exp 8×10°t 62.5 exp = 0.41205 62.5 = 0.3924 62.5 0.3924 62.5 0.3924 159.276= Vt 25368.923 s =t 25368.923 3600 t = 7.0469 hr.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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In the photos it show the steps to solve for t(time), I don't know how they got .3924 towards the end of part 1.
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