Please answer super fast please answer part (c) and (d) don’t forget to provide all steps please **Heat of Formation****Objective:** Use a standard enthalpies of formation table to determine the change in enthalpy for each of these reactions.**Reactions:**a) NaOH(s) + HCl(g) → NaCl(s) + H2O(g)b) 2 CO(g) + O2(g) → 2 CO2(g)c) CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l)d) 2 H2S(g) + 3 O2(g) → 2 H2O(l) + 2 SO2(g)e) 2 NO(g) + O2(g) → 2 NO2(g)**Standard Enthalpies of Formation (ΔHf) Table:**| Compound | ΔHf (kJ/mol) | Compound | ΔHf (kJ/mol) ||-----------|--------------|-----------|--------------|| CH4(g) | -74.8 | HCl(g) | -92.3 || CO2(g) | -393.5 | H2O(g) | -241.8 || NaCl(s) | -411.0 | SO2(g) | -296.1 || H2O(l) | -285.8 | NH4Cl(s) | -315.4 || H2S(g) | -20.1 | NO(g) | +90.4 || H2SO4(l) | -811.3 | NO2(g) | +33.9 || MgSO4(s) | -1278.2 | SnCl4(l) | -545.2 || MnO(s) | -384.9 | SnO(g) | -286.2 || MnO2(s) | -519.7 | SnO2(s) | -580.7 || NaCl(s) | -411.0 | SO3(g) | -395.2 || NaF(s) | -569.0 | ZnO(s) | -348.0 || NaOH(s) | -426.7 |

Answer:The change in standard enthalpy of the reaction is given bynp = represents the stoichiometric…

Answered: c) CH4(g) + 2 O2(g) → CO2(g) + 2 H₂O(1)…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Please answer super fast please answer part (c) and (d) don’t forget to provide all steps please

**Heat of Formation**

**Objective:** Use a standard enthalpies of formation table to determine the change in enthalpy for each of these reactions.

**Reactions:**

a) NaOH(s) + HCl(g) → NaCl(s) + H2O(g)

b) 2 CO(g) + O2(g) → 2 CO2(g)

c) CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l)

d) 2 H2S(g) + 3 O2(g) → 2 H2O(l) + 2 SO2(g)

e) 2 NO(g) + O2(g) → 2 NO2(g)

**Standard Enthalpies of Formation (ΔHf) Table:**

| Compound | ΔHf (kJ/mol) | Compound | ΔHf (kJ/mol) |
|-----------|--------------|-----------|--------------|
| CH4(g) | -74.8 | HCl(g) | -92.3 |
| CO2(g) | -393.5 | H2O(g) | -241.8 |
| NaCl(s) | -411.0 | SO2(g) | -296.1 |
| H2O(l) | -285.8 | NH4Cl(s) | -315.4 |
| H2S(g) | -20.1 | NO(g) | +90.4 |
| H2SO4(l) | -811.3 | NO2(g) | +33.9 |
| MgSO4(s) | -1278.2 | SnCl4(l) | -545.2 |
| MnO(s) | -384.9 | SnO(g) | -286.2 |
| MnO2(s) | -519.7 | SnO2(s) | -580.7 |
| NaCl(s) | -411.0 | SO3(g) | -395.2 |
| NaF(s) | -569.0 | ZnO(s) | -348.0 |
| NaOH(s) | -426.7 |

Expert Solution

Step 1: Introduction to the change in standard enthalpy of the reaction

Answer:

The change in standard enthalpy of the reaction is given by

$straight capital delta straight H subscript rxn superscript 0 equals sum straight n subscript straight p cross times straight capital delta straight H degree subscript straight f left parenthesis products right parenthesis minus sum straight n subscript straight r cross times straight capital delta straight H degree subscript straight f left parenthesis reactants right parenthesis$

n_p = represents the stoichiometric coefficients of the products,

n_r= represents the stoichiometric coefficients of thereactants

$straight capital delta straight H subscript straight f superscript 0$ = represents the standard enthalpies of formation

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