C₁ = MCP (Tw. final-Twinitial)m,.(Tsinitial--Ts final)CaseCupperSteelAluminumBrasMass of Materialwatermass988 g27 Jm83 9m988 9988988951 9m51 9mWatertemperature22.423,1c94.525.8DetermineMaterialtemperatureISIC233 c1900°cP RFinaltemperature93²عوامJ25.70°26. SCp

Name: C₁ = MCP (Tw. final-Twinitial)m,.(Tsinitial--Ts final)CaseCupperSteel
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Description: C₁ = MCP (Tw. final-Twinitial)m,.(Tsinitial--Ts final)CaseCupperSteelAluminumBrasMass of Materialwatermass988 g27 Jm83 9m988 9988988951 9m51 9mWatertemperature22.423,1c94.525.8DetermineMaterialtemperatureISIC233 c1900°cP RFinaltemperature93²عوامJ25.

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C₁ = Case m.Cp (T final-Twinitial) m,.(Tsinitial-T, final) Cupper Steel Aluminum Bras Mass of water 988 9 988 9889 hol se Material mass 27 Im 83 9m 51 9m sgm Water temperature 22.46² 21 24.5 25.8 Material temperature ISIC 233c 190c° Determine cP ? Final temperature १३ ( علم 25.700 26.5 Cp

C₁ = Case m.Cp (T final-Twinitial) m,.(Tsinitial-T, final) Cupper Steel Aluminum Bras Mass of water 988 9 988 9889 hol se Material mass 27 Im 83 9m 51 9m sgm Water temperature 22.46² 21 24.5 25.8 Material temperature ISIC 233c 190c° Determine cP ? Final temperature १३ ( علم 25.700 26.5 Cp

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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Problem 1.1MA

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SUBJECT: Thermodynamics 2 Answer in 5 decimal places and unit analysis.
L V2 hg,strekli= f •5°2g + z, + hpompa.f 2g v? P2 +zz + hearbin,s + hg,toplam p.V.D Re = Pg pg 1.11 |6.9 -1.8 log Re hx.yerel =EKs Wmil hx,toplam= hx,sarekli + hx.yeret 3.7 2g Протра wỷ/2 ENPY = g Nsp H =-(wr,V2t – wr,V14) ý= 2nr,b,V,m = 2trzb2V2.n 2g/ pompa girişi (gH)³/4 Pg Wmil.B PB (WB Wmla PA WB (DR (D' WA From the experiments performed on the pump (pump A) in a laboratory, the following values at the best efficiency point were obtained; cm³ kg DA 3D 15 ст, НА 3 240 ст, Va%3D 1500 PA = 998 Na = 1800 rev / minute and ve NApompa = 0,91 ст3 HB 610 ст, Рв kg 998 m3 ve Vp= 4100' %3D It would be desirable to design a new pump (pump B) with values. Accordingly, which of the following is the revolution number of the new pump? 2051 rev / minute 2512 rev / minute 2196 rev / minute 2378 rev / minute 1969 rev / minute
B) (best done on Friday) You drop your steel WonderWoman toy into a container of molten gold to give it some shiny new armor. mwonderWoman= 0.324 kg mgold = 0.50 kg To WonderWoman= 22.4 °C To gold= 2513 °C cwonderWoman = 460' kg°C Cgold = 129I kg°C a WonderWoman = 1.2 x 10/ °C a gold=1.4 x 10/ °C LFusion Wonder Woman = 262,000 J/kg LFusion Gold =67,000 J/kg Tmelting steel = 1510 °C a. Ignoring phase changes, at what T will WonderWoman and the gold reach thermodynamic equilibrium? b. Through this process, how much heat is gained by WonderWoman? Through this process, how much heat is lost by the gold? c. The melting point of gold is 1064°C (when cooling it becomes a solid at this temperature). Based on your answer to part (a), will the gold get cold enough to solidify around WonderWoman?
PROBLEM #5 SoNe for the masimum Compressi ve load: weight ratio 6f each pole Given: a) Concree pole (rectangular) dimensions of each unit : 30.m x 30 cm rectangular pole haximum compressive Streng th: 45 Mpa Mass lo00 kg ニ 6) Giant bamboo pole Chollow cyinder) outside diameter diameter 30 cm - 22 cm maxi mum compressive st reng th : Bo mpa inside mass :100 Rg pae (hollow cylinder) outs ide diameter = 30 cm C. Steel inside di ameter = 28 cm marimum compressi ve streng th = 200 mpa CO mass = 25o kg di) Wood Caylindrical, not hollow diameter = 30 cm markimum streng th- 1 mpa compressive Kg mass = 350 %3D
When The process is accorcing to a law iso thermal. takes place in a perfectly thermally b. C. insulated Cylinder. 8=1.3 Ans.[ 270 i 5.138 1g1.713 1J,52.6i,sSiky.-5.51, 219 5251g, o leg] University of Anbar College of Engineering Mechantont Englning Dpartment Year (Sophomore year) THERMODYNAMICSA Lec. No. Date: / 202 ME2303 Instructor: Asst. Prof. Dr. Saad M. Jalil hr Page Na. Q7 225 1g Ih of air at 4o% enter amixing chamber where it mixes with 540 kg /h of air at isi. Calculate the temperature of the air leaving the Chamber. assuming steady flow conditions. A ssume that the heat loss is negligible . Ans [22.4c] Q8: Aquantity of gas occupying o14n at a pressure of 1.4MNIM? and temperature of 300 č is expanded adiabatirally to 280 K Nimi Cv = 0. 74 Kg 11eg K p=1o41g ng - detennine: a. the mass of gas b. the temperature of the gas after expansion. work done during the expansion. Ans-fa-1.14 kg C. the b. ४३१ C. 180 lT ) Internal mC,(T2-T1) mC,(T2-T
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P1 + as 2g pg P2 +z, + hpompa.f L V² + z2 + h¢arbing +hx,toplam_hxsûrekli= f. pg 'D´2g Wmil hỵ̟toplam= hx,sûrekli + hx,yerel Nsp = (gH)³/4 hkyerel = 2g Протра 一()-)图)第-(=)G) 5 HB Wmil,B _ PB (WB PAlwa) DA Wmil,A WR (DB wWm/2 Ns = %3D WA (DA HA Wmil = PgHỳntarbin p1/2(gH)5/4 Wmil = prwv(V; – rw)(1 – cosß) At the best efficiency point with the experiments on the A turbine DA= 72 cm, HA= 20 m, V = 50 m/s, PA= 998 kg/m³, na= 205 revolution per minute , Wmila= 9 MW values have been obtained. PB= 998 kg/m³, HB= 65 m, nâ= 185 A new B turbine will be designed. According to this ; a) B is the volumetric flow of the turbine (VR) (m/s) find as. c) Find the specific speed of turbine B. b) Find the power of turbine B. (Wmil.B) 2.5 d) Find the diameter of turbine B. 285 245.3 MW 3,5 120 cm 361 211,5 MW O 2.8 156 cm 180 190 MW O 2,1 144 cm 255 182,7 MW O 31 O 104 cm 375 250 MW O 95 am O O
Unit systema) Determine the units of pressure in the equation pv=RT v: specific volume, m3/kg R: constant in kJ/kgK, T: temperature in K
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Nitrogen gas is confined in a cylinder and the pressure of the gas is maintained by a weight placed on the piston. The mass of the piston and the weight together is 200 lb. The acceleration due to gravity is 9.81 m/s?, the atmospheric pressure is one standard atmosphere and the friction diameter is 4 in. Assuming the piston is frictionless, determine the pressure of the gas in inches Hg. a. 46.10 c. 78.54 7. The molar composition of a gas is 10% H2, 10% O2, 30% CO2 and balance H2O. If 50% H20 condenses, the final mole percent of H2 in b. 22.65 d. 38.59