(C) a². 2х2 a²u Problem #3: Consider the following partial differential equations. a²u (A) a²x² + cx = - a²u at + c(L = x) a²u (B) k√x² I a²u = (D) a². дх a²u (E) k 2 2x2 hu = a²u atz a²u (F) k II I hu = C ди at II ди at ди It a²u (G) k + cx = ди at 2 и (H) a² a²u = Problem #3(a): B Problem #3(b): C Problem #3(c): A Problem #3(d): H มะ a²u In each part, determine which differential equation is the correct model for the given function. (a) A string of length L coincides with the interval [0,L] on the x-axis. Transverse vibrations are damped with a force proportional to the instantaneous velocity. u(x, t) is the displacement of the string. (b) A string of length L coincides with the interval [0,L] on the x-axis. An external vertical force proportional to the horizontal distance from the right end acts on the string for t>0. u(x, t) is the displacement of the string. (c) A rod of length L coincides with the interval [0,L] on the x-axis. u(x, t) is the temparature of the rod. (d) A string of length L coincides with the interval [0,L] on the x-axis. u(x, t) is the displacement of the string. Just Save Your work has been saved! (Back to Admin Page). Submit Problem #3 for Grading Problem #3 Your Answer: 3(a) E. Attempt #1 Attempt #2 Attempt #3 Attempt #4 Attempt #5 3(a) B 3(a) 3(a) 3(a) 3(b) C 3(b) 3(b) 3(b) 3(b) 3(c) G 3(c) A 3(c) 3(c) 3(c) 3(d) H 3(d) 3(d) 3(d) 3(d) Your Mark: 3(a) 0/1x 3(a) 0/1x 3(a) 3(a) 3(a) 3(b) 1/1 v 3(b) 3(b) 3(b) 3(b) 3(c) 0/1x 3(c) 0/1x 3(c) 3(c) 3(c) 3(d) 1/1 3(d) 3(d) 3(d) 3(d)
(C) a². 2х2 a²u Problem #3: Consider the following partial differential equations. a²u (A) a²x² + cx = - a²u at + c(L = x) a²u (B) k√x² I a²u = (D) a². дх a²u (E) k 2 2x2 hu = a²u atz a²u (F) k II I hu = C ди at II ди at ди It a²u (G) k + cx = ди at 2 и (H) a² a²u = Problem #3(a): B Problem #3(b): C Problem #3(c): A Problem #3(d): H มะ a²u In each part, determine which differential equation is the correct model for the given function. (a) A string of length L coincides with the interval [0,L] on the x-axis. Transverse vibrations are damped with a force proportional to the instantaneous velocity. u(x, t) is the displacement of the string. (b) A string of length L coincides with the interval [0,L] on the x-axis. An external vertical force proportional to the horizontal distance from the right end acts on the string for t>0. u(x, t) is the displacement of the string. (c) A rod of length L coincides with the interval [0,L] on the x-axis. u(x, t) is the temparature of the rod. (d) A string of length L coincides with the interval [0,L] on the x-axis. u(x, t) is the displacement of the string. Just Save Your work has been saved! (Back to Admin Page). Submit Problem #3 for Grading Problem #3 Your Answer: 3(a) E. Attempt #1 Attempt #2 Attempt #3 Attempt #4 Attempt #5 3(a) B 3(a) 3(a) 3(a) 3(b) C 3(b) 3(b) 3(b) 3(b) 3(c) G 3(c) A 3(c) 3(c) 3(c) 3(d) H 3(d) 3(d) 3(d) 3(d) Your Mark: 3(a) 0/1x 3(a) 0/1x 3(a) 3(a) 3(a) 3(b) 1/1 v 3(b) 3(b) 3(b) 3(b) 3(c) 0/1x 3(c) 0/1x 3(c) 3(c) 3(c) 3(d) 1/1 3(d) 3(d) 3(d) 3(d)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
No chatgpgt
![(C) a².
2х2
a²u
Problem #3: Consider the following partial differential equations.
a²u
(A) a²x² + cx =
-
a²u
at
+ c(L = x)
a²u
(B) k√x²
I
a²u
=
(D) a².
дх
a²u
(E) k 2
2x2
hu =
a²u
atz
a²u
(F) k
II
I
hu =
C
ди
at
II
ди
at
ди
It
a²u
(G) k
+ cx =
ди
at
2 и
(H) a²
a²u
=
Problem #3(a): B
Problem #3(b): C
Problem #3(c): A
Problem #3(d): H
มะ
a²u
In each part, determine which differential equation is the correct model for the given function.
(a) A string of length L coincides with the interval [0,L] on the x-axis. Transverse vibrations are damped with a
force proportional to the instantaneous velocity. u(x, t) is the displacement of the string.
(b) A string of length L coincides with the interval [0,L] on the x-axis. An external vertical force proportional to
the horizontal distance from the right end acts on the string for t>0. u(x, t) is the displacement of the string.
(c) A rod of length L coincides with the interval [0,L] on the x-axis. u(x, t) is the temparature of the rod.
(d) A string of length L coincides with the interval [0,L] on the x-axis. u(x, t) is the displacement of the string.
Just Save
Your work has been saved! (Back to Admin Page).
Submit Problem #3 for Grading
Problem #3
Your Answer: 3(a) E.
Attempt #1
Attempt #2
Attempt #3
Attempt #4
Attempt #5
3(a) B
3(a)
3(a)
3(a)
3(b) C
3(b)
3(b)
3(b)
3(b)
3(c) G
3(c) A
3(c)
3(c)
3(c)
3(d) H
3(d)
3(d)
3(d)
3(d)
Your Mark: 3(a) 0/1x
3(a) 0/1x
3(a)
3(a)
3(a)
3(b) 1/1 v
3(b)
3(b)
3(b)
3(b)
3(c) 0/1x
3(c) 0/1x
3(c)
3(c)
3(c)
3(d) 1/1
3(d)
3(d)
3(d)
3(d)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd5ab18a3-de3b-4185-9fff-fd0486dd1022%2F9631cd6c-3340-4828-a1d1-08dd089ac4ef%2F1dtgyem_processed.png&w=3840&q=75)
Transcribed Image Text:(C) a².
2х2
a²u
Problem #3: Consider the following partial differential equations.
a²u
(A) a²x² + cx =
-
a²u
at
+ c(L = x)
a²u
(B) k√x²
I
a²u
=
(D) a².
дх
a²u
(E) k 2
2x2
hu =
a²u
atz
a²u
(F) k
II
I
hu =
C
ди
at
II
ди
at
ди
It
a²u
(G) k
+ cx =
ди
at
2 и
(H) a²
a²u
=
Problem #3(a): B
Problem #3(b): C
Problem #3(c): A
Problem #3(d): H
มะ
a²u
In each part, determine which differential equation is the correct model for the given function.
(a) A string of length L coincides with the interval [0,L] on the x-axis. Transverse vibrations are damped with a
force proportional to the instantaneous velocity. u(x, t) is the displacement of the string.
(b) A string of length L coincides with the interval [0,L] on the x-axis. An external vertical force proportional to
the horizontal distance from the right end acts on the string for t>0. u(x, t) is the displacement of the string.
(c) A rod of length L coincides with the interval [0,L] on the x-axis. u(x, t) is the temparature of the rod.
(d) A string of length L coincides with the interval [0,L] on the x-axis. u(x, t) is the displacement of the string.
Just Save
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Submit Problem #3 for Grading
Problem #3
Your Answer: 3(a) E.
Attempt #1
Attempt #2
Attempt #3
Attempt #4
Attempt #5
3(a) B
3(a)
3(a)
3(a)
3(b) C
3(b)
3(b)
3(b)
3(b)
3(c) G
3(c) A
3(c)
3(c)
3(c)
3(d) H
3(d)
3(d)
3(d)
3(d)
Your Mark: 3(a) 0/1x
3(a) 0/1x
3(a)
3(a)
3(a)
3(b) 1/1 v
3(b)
3(b)
3(b)
3(b)
3(c) 0/1x
3(c) 0/1x
3(c)
3(c)
3(c)
3(d) 1/1
3(d)
3(d)
3(d)
3(d)
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