C = 2π201 lo (1) Eq. 8.12 is 24 = बैल Problem 8.2 Consider the charging capacitor in Prob. 7.34. (a) Find the electric and magnetic fields in the gap, as functions of the distance s from the axis and the time t. (Assume the charge is zero at t = 0.) (b) Find the energy density uem and the Poynting vector S in the gap. cially the direction of S. Check that Eq. 8.12 is satisfied. Note espe- (c) Determine the total energy in the gap, as a function of time. Calculate the total power flowing into the gap, by integrating the Poynting vector over the appro- priate surface. Check that the power input is equal to the rate of increase of energy in the gap (Eq. 8.9—in this case W = 0, because there is no charge in the gap). [If you're worried about the fringing fields, do it for a volume of radius b< a well inside the gap.] Problem 7.34 A fat wire, radius a, carries a constant current I, uniformly dis- tributed over its cross section. A narrow gap in the wire, of width w

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Problem 8.2 ple

C =
2π201
lo (1)
Eq.
8.12
is
24
=
बैल
Problem 8.2 Consider the charging capacitor in Prob. 7.34.
(a) Find the electric and magnetic fields in the gap, as functions of the distance s
from the axis and the time t. (Assume the charge is zero at t = 0.)
(b) Find the energy density uem and the Poynting vector S in the gap.
cially the direction of S. Check that Eq. 8.12 is satisfied.
Note espe-
(c) Determine the total energy in the gap, as a function of time. Calculate the total
power flowing into the gap, by integrating the Poynting vector over the appro-
priate surface. Check that the power input is equal to the rate of increase of
energy in the gap (Eq. 8.9—in this case W = 0, because there is no charge in
the gap). [If you're worried about the fringing fields, do it for a volume of radius
b< a well inside the gap.]
Transcribed Image Text:C = 2π201 lo (1) Eq. 8.12 is 24 = बैल Problem 8.2 Consider the charging capacitor in Prob. 7.34. (a) Find the electric and magnetic fields in the gap, as functions of the distance s from the axis and the time t. (Assume the charge is zero at t = 0.) (b) Find the energy density uem and the Poynting vector S in the gap. cially the direction of S. Check that Eq. 8.12 is satisfied. Note espe- (c) Determine the total energy in the gap, as a function of time. Calculate the total power flowing into the gap, by integrating the Poynting vector over the appro- priate surface. Check that the power input is equal to the rate of increase of energy in the gap (Eq. 8.9—in this case W = 0, because there is no charge in the gap). [If you're worried about the fringing fields, do it for a volume of radius b< a well inside the gap.]
Problem 7.34 A fat wire, radius a, carries a constant current I, uniformly dis-
tributed over its cross section. A narrow gap in the wire, of width w <a, forms
a parallel-plate capacitor, as shown in Fig. 7.45. Find the magnetic field in the gap,
at a distances <a from the axis.
a
+0
I
พ
FIGURE 7.45
Transcribed Image Text:Problem 7.34 A fat wire, radius a, carries a constant current I, uniformly dis- tributed over its cross section. A narrow gap in the wire, of width w <a, forms a parallel-plate capacitor, as shown in Fig. 7.45. Find the magnetic field in the gap, at a distances <a from the axis. a +0 I พ FIGURE 7.45
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